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Elis [28]
3 years ago
13

Calculate the initial (from rest) acceleration of a proton in a 5.00 x 10^6 N/C electric field (such as created by a research Va

n de Graaff). Explicitly show how you follow the steps in the Problem-Solving Strategy for electrostatics.
Physics
1 answer:
julsineya [31]3 years ago
5 0

Answer:

Acceleration of the proton will be equal to 4.79\times 10^{14}m/sec^2

Explanation:

We have given electric field E=5\times 10^6N/C

Mass of proton is equal to m=1.67\times 10^{-27}kg

And charge on proton is equal to e=1.6\times 10^{-19}C

Electrostatic force will be responsible for the motion of proton

Electrostatic force will be equal to F=qE=1.6\times 10^{-19}\times 5\times 10^6=8\times 10^{-13}N

According to newton law force on the proton will be equal to F = ma, here m is mass of proton and a is acceleration

This newton force will be equal to electrostatic force

So 1.67\times 10^{-27}\times a=8\times 10^{-13}

a=4.79\times 10^{14}m/sec^2

So acceleration of the proton will be equal to 4.79\times 10^{14}m/sec^2

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