A rocket travels 19,500 miles in just 45 seconds. What is the speed of the rocket in miles per hour during the 45 seconds?

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B27%7D%20%20%5Ctimes%20%20%5Csqrt%7B75%7D%20" id="TexFormula1" title=" \sqrt{27}

Harman [31]

Answer:

44.95

Step-by-step explanation:

$\sqrt{27} \times \sqrt{75 } \\ = 5.19 \times 8.66 \\ 44.9454$

Two decimal places = 44.95

5 0

3 years ago

in a certain pentagon, the interior angles are a,b,c,d,e where a,b,c,d,e are integers strictly less than 180. ("Strictly less th

guajiro [1.7K]

Answer:

least to greatest: {61, 61, 61, 178, 179}

Step-by-step explanation:

If the third-largest angle is 61°, the smallest three angles cannot be larger than 183°. Since the total of all angles must be 540°, and the total of the largest two cannot be greater than 179°×2 = 358°, the sum of the smallest three must be at least 540° -358° = 182°.

So, the possible sets of angles with the smallest 3 totaling 182° or 183° are (in degrees) ...

{60, 61, 61, 179, 179} . . . . two modes

(61, 61, 61, 178, 179} . . . . . one mode -- the set you're looking for

3 0

3 years ago

Read 2 more answers

Here is my question please answer and give a good explanation: Which expression cannot be used to calculate the total amount pai

Ierofanga [76]

I'm pretty sure the answer is D. because I don't think anyone would want to take their total meal cost and then multiply it by their tip to make it even larger. You would just add the tip to the meal cost.

6 0

3 years ago

300 Less Than 3 tenths

Ksju [112]

The answer is -299.7

4 0

3 years ago

O is the centre of the circle, EF is a tangent, angle BCE = 28°, angle ACD = 31°

andriy [413]

Answer

a. 28˚

b. 76˚

c. 104˚

d. 56˚

Step-by-step explanation

Given,

∠BCE=28° ∠ACD=31° & line AB=AC .

According To the Question,

a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°

b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚

thus , ∠ABC=76° .

c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,

Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°

Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)

∠DAB = 180° - 107° ⇔ 73°

& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°

Now, In Triangle ADC Sum of angles in a triangle is 180°

∠ADC = 180° - (31° + 45°) ⇔ 104˚

d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre

For Diagram, Please Find in Attachment

4 0

3 years ago