Answer:
Set it up as a table and insert the numbers one by one
Answer:
Step-by-step explanation:
You can start this in may ways but let's start by isolating one of the parenthesis:
x (x² - 5) = - (x - 3)
x³ - 5x = -x + 3 (here I multiplied x for what's inside the parenthesis and the "minus" signal by the other parenthesis which was (x - 3))
x³ - 5x + x = 3
x³ -4x = 3
x³ -4x -3 = 0 (now this right here is a "depressed cubic equation" and it's one of the toughest sit of all time, so good luck with that, you might wanna take a look at this:
ytb/watch?v=rNDy2ZFvG1E
or maybe I'm doing something wrong and it's simpler than that, but whaterver...)
Answer:
Step-by-step explanation:
Answer: 
Step-by-step explanation:
Given
Complex number is 
Its conjugate is obtained by changing the sign of the original number i.e. 
The product of the two numbers is
![\Rightarrow (2-i5)(2+i5)=2^2-(5i)^2\quad \quad [(x+y)(x-y)=x^2-y^2]\\\\\Rightarrow (2-i5)(2+i5)=4-25i^2\\\\\Rightarrow (2-i5)(2+i5)=4+25=29](https://tex.z-dn.net/?f=%5CRightarrow%20%282-i5%29%282%2Bi5%29%3D2%5E2-%285i%29%5E2%5Cquad%20%5Cquad%20%5B%28x%2By%29%28x-y%29%3Dx%5E2-y%5E2%5D%5C%5C%5C%5C%5CRightarrow%20%282-i5%29%282%2Bi5%29%3D4-25i%5E2%5C%5C%5C%5C%5CRightarrow%20%282-i5%29%282%2Bi5%29%3D4%2B25%3D29)