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bulgar [2K]
3 years ago
8

Select the unitless quantities: a, absorbance c, solute concentration i/i0 (ratio of emergent to incident intensity) b, pathleng

th
Chemistry
1 answer:
lianna [129]3 years ago
8 0
Absorbance is unitless by definition, this is the fraction of light absorbed.
Solute concentration will have mol/L units, so it is not unitless.
i/i0 (ratio of emergent to incident intensity) is similar to absorbance, and the units will cancel out, making this unitless.
Path length will have a unit in millimeters or centimeters, so it is not unitless.

Therefore the unitless quantitites are absorbance and intensity ratio.
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A sample of an ideal gas has a volume of 3.25 L at 12.80 °C and 1.50 atm. What is the volume of the gas at 24.40 °C and
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3 years ago
Acetic acid has a heat of fusion of 10.8 kJ/mol and a heat of vaporization of 24.3 kJ/mol. What is the expected value for the he
photoshop1234 [79]

Answer: 35.1 kJ/mol

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

CH_3COOH(s)\rightarrow CH_3COOH(l)    \Delta H_{fusion}=10.8kJ/mol   (1)

CH_3COOH(l)\rightarrow CH_3COOH(g)    \Delta H_{vap}=24.3kJ/mol   (1)

The final reaction is:  

CH_3COOH(s)\rightarrow CH_3COOH(g)  \Delta H_{sub}=?   (3)

By adding (1) and (2)

\Delta H_{sub}=\Delta H_{fusion}+\Delta H_{sub}=+10.8kJ+(+24.3kJ)=35.1kJ

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6 0
3 years ago
The nonvolatile, nonelectrolyte estrogen (estradiol), C18H24O2 (272.40 g/mol), is soluble in chloroform CHCl3.
Artist 52 [7]

<u>Answer:</u> The molarity of solution is 0.274 M and the osmotic pressure of the solution is 6.70 atm

<u>Explanation:</u>

To calculate the molarity of the solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Given mass of estrogen = 13.5 g

Molar mass of estrogen = 272.40 g/mol

Volume of solution = 181 mL

Putting values in above equation, we get:

\text{Molarity of solution}=\frac{13.5\times 1000}{272.40\times 181}\\\\\text{Molarity of solution}=0.274M

Hence, the molarity of solution is 0.274 M

To calculate the osmotic pressure of the solution, we use the equation:

\pi=iMRT

where,

\pi = osmotic pressure of the solution = ?

i = Van't hoff factor = 1 (for non-electrolytes)

M = molarity of solute = 0.274 M

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature of the solution = 298 K

Putting values in above equation, we get:

\pi=1\times 0.274mol/L\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\\pi=6.70atm

Hence, the osmotic pressure of the solution is 6.70 atm

8 0
3 years ago
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