Answer:
Heres a picture of the periodic table.
Explanation:
Source(s):Science News for Students
A monkey needs to use more force and strength than a bat when swinging and they can get more momentum to push forward. and bat needs shorter limbs so they don’t have much weight to carry when they are flapping their wings. they will go faster with less mass in their arms.
6.6 ×
J = 6.2 ×
British thermal units
First of all, we should know that 1 British thermal unit = 1055 Joules.
From question, heat = 6.6 ×
J
1 BTU = 1055 J
6.6 ×
J =
× 6.6 ×
British thermal units
= 6.2 ×
British thermal units
1000 Joules = 1 kilojoule
A kilojoule is a unit of measure of energy, in the equal way that kilometers degree distance. meals energy used to be measured in energy and some international locations still use those gadgets.
The power we get from foods and drinks is measured in kilojoules. that is the metric time period for calorie. Kilojoules and energy constitute the equal aspect. One calorie is ready four kilojoules.
Calorie a unit for measuring warmth same to the quantity of warmth required to elevate the temperature of one gram of water one diploma Celsius.
Learn more about kilojoules here :- brainly.com/question/490326
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Combustion reaction for menthol is as follows;
CxHyOz + O₂ ---> xCO₂ + H₂O
Mass of CO₂ formed - 28.16 mg
Therefore number of moles formed - 28.16/ 44 g/mol = 0.64 mmol
Mass of water formed - 11.53 mg
number of water moles formed - 11.53 mg/18 g/mol = 0.64 mmol
From CO₂,
1 mol of CO₂ - 1 mol of C and 2 mol of O
therefore number of C moles - 0.64 mmol
O moles - 1.28 mmol
from H₂O
1 mol of H₂O - 2 mol of H and 1 mol of O
number of H moles - 1.28 mmol
O moles - 0.64 mmol
Mass of menthol initially - 10 mg
in reactions, the masses of products are equal to the masses of reactants. The excess mass to the products formed is due to O₂ in air
Original mass of menthol - 10 mg
mass of water and CO₂ - 11.53 mg + 28.16 mg = 39.69
Difference in mass - 39.69 - 10 = 29.69 mg
This difference comes from O moles in air - 29.69 mg/ 16 g/mol = 1.8556 mmol
then O moles coming from menthol - (1.28 + 0.64) - 1.8556 = 0.064 mmol
In menthol
C moles - 0.64 mmol
H moles - 1.28 mmol
O moles - 0.064 mmol
ratios of C:H:O
C H O
0.64 1.28 0.064
x1000 x1000 x1000 to get whole numbers
640 1280 64
10 20 1
Simplest ratio of C:H:O is 10:20:1
therefore empirical formula of menthol is C₁₀H₂₀O