Question

what volume of ethylene gas at 293K and 102kPa must be compressed to yield 295m3 of ethylene gas at 808kPa and 585K​

Answer 1

Answer:

1170.43 m³

Explanation:

We are given;

• Initial pressure, P1 as 808 kPa
• Initial temperature, T1 as 585 K
• Initial volume, V1 as 295 m³
• New pressure, P2 as 102 kPa
• New temperature, T2 as 293 K

We are required to find the new volume;

• We are going to use the combined gas law
• According to the gas law;  $\frac{P1V1}{T1}=\frac{P2V2}{T2}$
• Thus, rearranging the formula;

$V2=\frac{P1V1T2}{P2T1}$

$V2=\frac{(808 kPa)(295)(293K)}{(102 kPa)(585K)}$

$V2=1170.43$

Therefore, the volume is 1170.43 m³