A reaction x y has a rate constant of 1.37 hr–1 and is allowed to react for 1.2 hours. if the final concentration of x is 0.21
m, what was the original concentration of x?
1 answer:
The unit measurement of the rate constant is a guide to tell you the rate order. If it's unit is 1/time, then it is a first-order reaction. From the picture attached, the formula to be used would be:
ln[A] = ln[A₀] - kt
ln[0.21] = ln[A₀] - (1.37)(1.2)
Solving for A₀,
A₀= 1.09 M
<em>Hence, the original concentration of X was 1.09 M.</em>
ln[A] = ln[A₀] - kt
ln[0.21] = ln[A₀] - (1.37)(1.2)
Solving for A₀,
A₀= 1.09 M
<em>Hence, the original concentration of X was 1.09 M.</em>
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Answer:
Explanation:
We have to start with the <u>reaction</u>:
We have the same amount of atoms on both sides, so, we can continue. The next step is to find the <u>number of moles</u> that we have in the 110.0 g of carbon dioxide, to this, we have to know the <u>atomic mass of each atom</u>:
C: 12 g/mol
O: 16 g/mol
Mg: 23.3 g/mol
If we take into account the number of atoms in the formula, we can calculate the <u>molar mass</u> of carbon dioxide:
In other words: . With this in mind, we can calculate the moles:
Now, the <u>molar ratio</u> between carbon dioxide and magnesium carbonate is 1:1, so:
With the molar mass of (
. With this in mind, we can calculate the <u>grams of magnesium carbonate</u>:
I hope it helps!