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Answer:
The correct answer is 0.206 moles
Explanation:
According to the given scenario, the calculation of the number of moles of ammonium chloride is available in the resulting solution is given below:
Given that
Amount of
is 11.0 grams
And, the volume is 235 mL
Now the molar mass of
is 53.49g/mol
So, the number of moles presented is
= 11.0 ÷ 53.49
= 0.206 moles
hence, the number of moles of ammonium chloride are available in the resulting solution is 0.206 moles
Balanced equation:
Mg + 2 HNO3 —> Mg(NO3)2 + H2
This is a metal + acid reaction giving salt and hydrogen (not water).