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MaRussiya [10]
3 years ago
12

A reaction x  y has a rate constant of 1.37 hr–1 and is allowed to react for 1.2 hours. if the final concentration of x is 0.21

m, what was the original concentration of x?

Chemistry
1 answer:
lawyer [7]3 years ago
5 0
The unit measurement of the rate constant is a guide to tell you the rate order. If it's unit is 1/time, then it is a first-order reaction. From the picture attached, the formula to be used would be:

ln[A] = ln[A₀] - kt
ln[0.21] = ln[A₀] - (1.37)(1.2)
Solving for A₀,
A₀= 1.09 M

<em>Hence, the original concentration of X was 1.09 M.</em>

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For the reaction o(g) + o2(g) → o3(g) δh o = −107.2 kj/mol given that the bond enthalpy in o2(g) is 498.7 kj/mol, calculate the
Aneli [31]
The reaction;
O(g) +O2(g)→O3(g), ΔH = sum of bond enthalpy of reactants-sum of food enthalpy of products.
ΔH = ( bond enthalpy of O(g)+bond enthalpy of O2 (g) - bond enthalpy of O3(g)
-107.2 kJ/mol = O+487.7kJ/mol =O+487.7 kJ/mol +487.7kJ/mol =594.9 kJ/mol
Bond enthalpy (BE) of O3(g) is equals to 2× bond enthalpy of O3(g) because, O3(g) has two types of bonds from its lewis structure (0-0=0).
∴2BE of O3(g) = 594.9kJ/mol
Average bond enthalpy = 594.9kJ/mol/2
=297.45kJ/mol
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3 years ago
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Sophie [7]
Quick answer: Exothermic reactions mean that heat has escaped the system. The answer is A. Heat is released.
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Determine the number of moles of iodine that reacts with 50g of aluminum​
frozen [14]

Answer: The correct answer is option B i.e., 2.78 mol

Explanation:

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$2Al(s)+3I_{2}(s) \to Al_{2}I_{6}(s)$

From the equation, it is clear that 3 moles of iodine reacts with 2 moles of Aluminium to form Aluminium iodide

We know $No.\,of\,moles=\frac{weight}{molecular\,weight} \\

For 2 moles of Aluminium, $2=\frac{weight}{27}$\\ $weight=2 \times 27=54g$

3 moles of Iodine reacts with 54 g of Aluminium

? moles of iodine react with 50 g of Aluminium

$=\frac{3 \times 50}{54} =2.78 mol$

8 0
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1. Naturally occurring europium (Eu) consists of two isotopes was a mass of 151 and 153. Europium- 151 has an abundance of 48.03
sergejj [24]
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klasskru [66]

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