Explanation:
H= mass× specific heat capacity×change in temperature
=2×380×(10-0)
=2×380×10
=7600Joules
<span>1.0x10^3 Joules
The kinetic energy a body has is expressed as the equation
E = 0.5 M V^2
where
E = Energy
M = Mass
V = Velocity
Since the shot was at rest, the initial energy is 0. Let's calculate the energy that the shot has while in motion
E = 0.5 * 7.2 kg * (17 m/s)^2
E = 3.6 kg * 289 m^2/s^2
E = 1040.4 kg*m^2/s^2
E = 1040.4 J
So the work performed on the shot was 1040.4 Joules. Rounding the result to 2 significant figures gives 1.0x10^3 Joules</span>
The volume of water in the larger balloon is 8 times greater than in the smaller balloon
We'll begin by calculating the volume of each balloon.
<h3>For smaller balloon:</h3>
- Radius (r) = 3 cm
- Pi (π) = 3.14
- Volume (V) =?
V = 4/3 πr³
V = 4/3 × 3.14 × 3³
<h3>V = 113.04 cm³</h3>
<h3>For larger balloon:</h3>
- Radius (r) = 6 cm
- Pi (π) = 3.14
- Volume (V) =?
V = 4/3 πr³
V = 4/3 × 3.14 × 6³
<h3>V = 904.32 cm³</h3>
Finally, we shall determine how much greater the larger balloon is to the smaller balloon
- Volume of smaller balloon = 113.04 cm³
- Volume of larger balloon = 904.32 cm³
- Greatness =?
Greatness => large / small
Large / small = 904.32 / 113.04
Large / small = 8
Cross multiply
<h3>Large = 8 × small </h3>
Therefore, the larger balloon is 8 times greater than the smaller balloon.
Learn more on volume of sphere: brainly.com/question/9178703
