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ANTONII [103]
2 years ago
11

Which of these types of changes is a physical change?

Chemistry
2 answers:
Degger [83]2 years ago
7 0
The answer is a because the other ones are chemical
Leto [7]2 years ago
6 0

The correct answer is A. Can I get the Brainliest?

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____________ is refining the extracted raw metals into a purest form
Alex

Answer:

Extractive metallurgy

Explanation:

Extractive metallurgy is the practice of removing valuable metals from an ore and refining the extracted raw metals into a purer form.

8 0
3 years ago
Why sulphur has two melting point values
Fofino [41]

I don't know how well known/accepted this is (it's in my textbook so I'm guessing it's right), but Sulphur has two forms - the alpha and beta forms ,apparently gamma sulphur exists as well.

The alpha form is rhombic, yellow in color and has a MP of 385.8 K. The beta form is colorless and has a MP of 393 K and is formed by melting rhombic sulphur and cooling it till a crust forms on top. Poke a hole and pour out the liquid inside and you get beta sulphur. The transition point is 369K - below it, alpha sulphur is stable and above it, beta sulphur is stable. Both have helped. I had to pull out an old textbook and that's something that I don't usually do.

8 0
2 years ago
What happens as a liquid freezes?
Sindrei [870]
The particles bunch together and can no longer move
8 0
3 years ago
Read 2 more answers
All the following are oxidation–reduction reactions except:________
Blizzard [7]

Answer:

e. Mg₃N₂(s) + 6H₂O(l) → 3Mg(OH)₂(s) + 2NH₃(g)

Explanation:

All the following are oxidation–reduction reactions except:________

a. H₂(g) + F₂(g) → 2HF(g).  Redox. H is oxidized and F is reduced.

b. Ca(s) + H₂(g) → CaH₂(s).  Redox. Ca is oxidized and H is reduced.

c. 2K(s) + 2H₂O(l) → 2KOH(aq) + H₂(g).  Redox. K is oxidized and H is reduced.

d. 6Li(s) + N₂(g) → 2Li₃N(s).  Redox. Li is oxidized and N is reduced.

e. Mg₃N₂(s) + 6H₂O(l) → 3Mg(OH)₂(s) + 2NH₃(g). Not redox. All the elements have the same oxidation number

5 0
3 years ago
In state n = 1, the energy of the hydrogen atom is -13.58 ev. what is its energy in state n = 2?
Gekata [30.6K]

The energy of a hydrogen atom in energy level n = 2 is 3.4 eV.

The ionization of energy of the hydrogen atom is 13.6 eV.

This is the minimum energy required to raise the electron from its ground state in the hydrogen atom.

n represents the Energy level.

When an electron changes from one energy level to another, the energy of the atom must change as well.  It requires energy to promote an electron from a lower energy level to a higher one.  This energy can be supplied by a photon whose energy E is given in terms of its frequency E = hf or wavelength E = hc/λ.

The formula for the energy of an atom is:

E = 13.6 * Z^{2} / n^{2}  .... this represents the allowed energy level in the hydrogen       atom

  = 13.6 * 1 / 2^{2}    since Z = 1 for hydrogen where Z is mass of atom

  = 13.6 / 4

  = 3.4 eV

The energy of a hydrogen atom in energy level n = 2 is 3.4 eV.

Find more information by clicking on the link below:

brainly.com/question/14287666

# SPJ4

8 0
1 year ago
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