Explain why your body feels like it is being pushed back when the car starts back up again

Physics

2 answers:

Masteriza [31]3 years ago

8 0

<h2>Answer:</h2>

<u>This push is felt due to inertia</u>

<h2>Explanation:</h2>

Inertia is the resistance, of any physical object, to any change in its velocity. This property is also called the first law of motion which says a body in rest will remain at rest and a body in motion will stay in motion until an external force acts upon them. The same thing happens when our body is at rest and the car suddenly starts backing up again. Because the rest state of our body experiences a sudden push and our body resist it due to inertia.

Fittoniya [83]3 years ago

3 0

Answer:

Due to inertia.

Explanation:

As per law of inertia, a body will remain in its state of motion until an external force, unbalanced in nature, is applied on it. When the car is at rest, the person sitting in it will also be at rest. When the car suddenly moves, the body resist the motion due to inertia and it stays in initial position while the car moves. Due to this the body will be pushed back.

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3 years ago

Determine the kinetic of 600 kg roller coaster car that is moving with the speed of 35.2 m/s.

antiseptic1488 [7]

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Explanation:

Step 1: Calculate
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3 years ago

A large power plant generates electricity at 12.0 kV. Its old transformer once converted the voltage to 385 kV. The secondary of

enot [183]

Answer:

a) In the new transformer there are 42 turns in the secondary per turn in the primary, while in the old transformer there were 32 turns per turn in the primary.

b) The new output is 86% of the old output

c) The losses in the new line are 74% the losses in the old line.

Explanation:

a) To relate the turns of primary and secondary to the ratio of voltage we have this expression:

$\frac{n_1}{n_2}=\frac{V_1}{V_2}$

In the old transformer the ratio of voltages was:

$\frac{n_1}{n_2}=\frac{V_1}{V_2}=\frac{12}{385} =0.03117\\\\n_2=n_1/0.03117=32.1n_1$

In the new transformer the ratio of voltages is:

$\frac{n_1}{n_2}=\frac{V_1}{V_2}=\frac{12}{500} =0.024\\\\n_2=n_1/0.24=41.7n_1$

In the new transformer there are 42 turns in the secondary per turn in the primary, while in the old transformer there were 32 turns per turn in the primary.

b) The new current ratio is

$\frac{V_1}{V_2}=\frac{I_2}{I_1}=\frac{12}{500}= 0.024\\\\I_2=0.024I_1$