Answer:
Centripetal Acceleration
In the previous section, we defined circular motion. The simplest case of circular motion is uniform circular motion, where an object travels a circular path at a constant speed. Note that, unlike speed, the linear velocity of an object in circular motion is constantly changing because it is always changing direction. We know from kinematics that acceleration is a change in velocity, either in magnitude or in direction or both. Therefore, an object undergoing uniform circular motion is always accelerating, even though the magnitude of its velocity is constant.
You experience this acceleration yourself every time you ride in a car while it turns a corner. If you hold the steering wheel steady during the turn and move at a constant speed, you are executing uniform circular motion. What you notice is a feeling of sliding (or being flung, depending on the speed) away from the center of the turn. This isn’t an actual force that is acting on you—it only happens because your body wants to continue moving in a straight line (as per Newton’s first law) whereas the car is turning off this straight-line path. Inside the car it appears as if you are forced away from the center of the turn. This fictitious force is known as the centrifugal force. The sharper the curve and the greater your speed, the more noticeable this effect becomes.
Figure shows an object moving in a circular path at constant speed. The direction of the instantaneous tangential velocity is shown at two points along the path. Acceleration is in the direction of the change in velocity; in this case it points roughly toward the center of rotation. (The center of rotation is at the center of the circular path). If we imagine Δs becoming smaller and smaller, then the acceleration would point exactly toward the center of rotation, but this case is hard to draw. We call the acceleration of an object moving in uniform circular motion the centripetal acceleration ac because centripetal means “center seeking.”
Explanation:
<span>we know energy = power*time(in hour)
so energy used by 1.20kw(1200 watt) toast oven used for 6.2 min(6.2/60 hour) =
1200*(6.2/60)=1200*0.103 = 124 watt hour.
Energy used by 11 w cfl used for 8.50 hour = (11*8) + (11* (50/60)) = 88+9.166=97.166 watt hour.</span>
The weight of the meterstick is:
and this weight is applied at the center of mass of the meterstick, so at x=0.50 m, therefore at a distance
from the pivot.
The torque generated by the weight of the meterstick around the pivot is:
To keep the system in equilibrium, the mass of 0.50 kg must generate an equal torque with opposite direction of rotation, so it must be located at a distance d2 somewhere between x=0 and x=0.40 m. The magnitude of the torque should be the same, 0.20 Nm, and so we have:
from which we find the value of d2:
So, the mass should be put at x=-0.04 m from the pivot, therefore at the x=36 cm mark.
Temperature. X-axis is always the independent variable.
Answer:
4/5 houses
Explanation:
The speed of the first carpenter is:
(1/5 house) / (3/4 day) = 4/15 house/day
The speed of the second carpenter is:
(2/5 house) / (3/4 day) = 8/15 house/day
Together, their combined speed is:
4/15 house/day + 8/15 house/day = 12/15 house/day
= 4/5 house/day
Per day, the two carpenters build 4/5 of a house.
