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Ad libitum [116K]

3 years ago

8

Please select the word from the list that best fits the definition

2 answers:

almond37 [142]3 years ago

4 0

The broadest level of organization would be the domain

olganol [36]3 years ago

3 0

The answer to this would be domain.

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What do radio waves and microwaves have in common?

Tamiku [17]

Answer:

I Will say the Answer is A

Explanation:

5 0

2 years ago

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Average weather conditions in a specific location for a long time

masya89 [10]

Answer:

B- the climate

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2 years ago

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If a blender is plugged into a 168 V outlet that supplies 80.8 A of current, what amount of

VladimirAG [237]

Answer:

Power = 13.5744 kilowatts

Explanation:

Power is the rate at which work is done. ... Great power means a large amount of work or energy developed in a short time. For example, when a powerful car accelerates rapidly, it does a large amount of work and consumes a large amount of fuel in a short time.

Formula for power = work/time

= IVT/T

= IV

Where I is the current

And V is the voltage

The voltage V supply = 168 v

The current A supply = 80.8 A

Power = 80.8*168

Power = 13574.4 watts

Power = 13.5744 kilowatts

5 0

2 years ago

What is a heat pump? Why does it need to put in external work? Help ASAP!

pishuonlain [190]

A heat pump is a device that puts out heat. It involves pumping a lever over and over to get energy so it can work.

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2 years ago

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The roller coaster car has a mass of 700 kg, including its passenger. If it is released from rest at the top of the hill A, dete

sweet [91]

Answer:

$h = 18.75 m$

Now when it will reach at point B then its normal force is just equal to ZERO

$N_B = 0$

$F_n = 1.72 \times 10^4$

Explanation:

Since we need to cross both the loops so least speed at the bottom must be

$v = \sqrt{5 R g}$

also by energy conservation this is gained by initial potential energy

$mgh = \frac{1}{2}mv^2$

$v = \sqrt{2gh}$

so we will have

$\sqrt{2gh} = \sqrt{5Rg}$

now we have

$h = \frac{5R}{2}$

here we have

R = 7.5 m

so we have

$h = \frac{5(7.5)}{2}$

$h = 18.75 m$

Now when it will reach at point B then its normal force is just equal to ZERO

$N_B = 0$

now when it reach point C then the speed will be

$mgh - mg(2R_c) = \frac{1}{2]mv_c^2$

$v_c^2 = 2g(h - 2R_c)$

$v_c = 13.1 m/s$

now normal force at point C is given as

$F_n = \frac{mv_c^2}{R_c} - mg$

$F_n = \frac{700\times 13.1^2}{5} - (700 \times 9.8)$

$F_n = 1.72 \times 10^4$

7 0

3 years ago