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gregori [183]
3 years ago
9

A physics book is thrown horizontally at a velocity of 5.0 m/s from the top of a cliff 78.4 m high. How long does the book take

to reach the bottom of the cliff .
Physics
1 answer:
xenn [34]3 years ago
3 0

The book's vertical position in the air is

y=78.4\,\mathrm m-\dfrac12gt^2

where g=9.80\,\frac{\mathrm m}{\mathrm s}. It reaches the ground when y=0, at a time t such that

0=78.4\,\mathrm m-\dfrac12gt^2\implies t=4.00\,\mathrm s

So it takes the book 4 seconds to reach the bottom. The given initial velocity is irrelevant since it only has a horizontal component; vertically, the book is starting from rest.

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When do we experience conservation of energy
Lerok [7]

Always, whether we notice it or not. It's a law of nature.

4 0
3 years ago
How long does it take a person to skate the width of a hockey rink (85 feet) at a constant speed of 15 feet per second?
Zepler [3.9K]
S(travel distance)=85 ft
v (velocity)=15 ft/s
-----------------------------------
t (time)=?

Calculate the time with the formula for the velocity:
v=S/t
t=S/v
t=85 ft/(15 ft/s)
t=5.666s
3 0
3 years ago
Chegg Given that the mean radius of the Moon’s orbit is 3.84 x 108 m and its period is 2.36 x 106 sec, at what altitude above th
alukav5142 [94]

Answer:

The altitude of geostationary satellite is 3.58\times10^{7}\ m

Explanation:

Given that,

Radius of moon's orbit r=3.84\times10^{8}\ m

Time period T=2.36\times10^{6}\ sec

We need to calculate the orbital radius of geostationary satellite is

Using formula of time period

T=\sqrt{\dfrac{4\pi^2}{GM}a^3}

a=((\dfrac{GM}{4\pi^2})T^2)^{\dfrac{1}{3}}

Where, G = gravitational constant

M = Mass of earth

T = time period of geostationary satellite orbit

Put the value in to the formula

a=((\dfrac{6.67\times10^{-11}\times5.97\times10^{24}}{4\times\pi^2})\times(86160)^2)^{\dfrac{1}{3}}

a=4.217\times10^{7}\ m

We need to calculate the altitude of geostationary satellite

Using formula of altitude

h = a-R_{e}

Where, R = radius of earth

a = radius of geostationary satellite

Put the value into the formula

h =4.217\times10^{7}-6.38\times10^{6}

h =35790000\ m

h=3.58\times10^{7}\ m

Hence, The altitude of geostationary satellite is 3.58\times10^{7}\ m

4 0
3 years ago
If the architectural plans show the rough opening of a window to be 3'-3" x 4'-9" , the height of the opening should actually me
tatyana61 [14]

Answer:

height of the opening actually measure is 4'-9"

Explanation:

given data

window size = 3'-3" x 4'-9"

solution

height of the opening should actually measure will be 4'-9" in 3'-3" x 4'-9"

because according to architectural plan height can not be more than the opening size of window

and we can't take smaller height also

so fit in opening window we should take same height of  height of opening window and that is here 4'-9"

so here height of the opening actually measure is 4'-9"

5 0
3 years ago
Help for brainlist easy science plz
zalisa [80]

Answer:

the pics upside down fam

Explanation:

6 0
2 years ago
Read 2 more answers
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