Explanation:
In the picture, I hope that it's a clear solution.
Answer:
549.9 ohms, 65.65 watts, the power went up
Explanation: power P = V²/R
v= 190volts , P =62watts
from P =V²/R
62=190²/R
making R the subject
R×62= 190²
62R =36100
R=36100/62
R=586.25 ohms
Resistance of each lamp = 586.26/18 =32.3ohms
a) resistance of the light string now = 17×32.3 = 549.9 ohms
b) P=V²/R
where R=549.9ohms , P=?
P=190²/549.9
P=36100/549.9
P=65.65watts
Power dissipated has increased( went up )
Answer:
Option D: More than 90
Explanation:
Thickness probably depends on temperature. The higher the temperature, the more aliens we expect to be thin.
Answer:
Speed = 5 m/s
Explanation:
Distance (d) = 10 m
Time (t) = 2 s
Speed = Distance ÷ Time
Speed = 10 ÷ 2
<em><u>Speed = 5 m/s</u></em>
Answer:
A u = 0.36c B u = 0.961c
Explanation:
In special relativity the transformation of velocities is carried out using the Lorentz equations, if the movement in the x direction remains
u ’= (u-v) / (1- uv / c²)
Where u’ is the speed with respect to the mobile system, in this case the initial nucleus of uranium, u the speed with respect to the fixed system (the observer in the laboratory) and v the speed of the mobile system with respect to the laboratory
The data give is u ’= 0.43c and the initial core velocity v = 0.94c
Let's clear the speed with respect to the observer (u)
u’ (1- u v / c²) = u -v
u + u ’uv / c² = v - u’
u (1 + u ’v / c²) = v - u’
u = (v-u ’) / (1+ u’ v / c²)
Let's calculate
u = (0.94 c - 0.43c) / (1+ 0.43c 0.94 c / c²)
u = 0.51c / (1 + 0.4042)
u = 0.36c
We repeat the calculation for the other piece
In this case u ’= - 0.35c
We calculate
u = (0.94c + 0.35c) / (1 - 0.35c 0.94c / c²)
u = 1.29c / (1- 0.329)
u = 0.961c
