Answer:
1.18266×10⁻²⁰ J
Explanation:
Applying,
E = (3/2)kT.................... Equation 1
Where E = kinetic energy of the gas molecule, k = Boltzmann's constant, T = Temperature
But,
PV = nRT.............. Equation 2
Where P = pressure, V = Volume, n = number of moles, R = Universal gas constant.
make T the subject of the equation
T = PV/nR............. Equation 3
Substitute equation 3 into equation 1
E = (3/2)k(PV/nR)
E = 3kPV/2nR............... Equation 4
Given: k = 1.38066×10⁻²³ J/K, V = 6.6 L = 0.0066 m³, P = 7.1 atm = (101325×7.1) N/m² = 719407.5 N/m², n = 2.9 mol, R = 8.31451 J/K.mol
Substitute into equation 4
E = (3×1.38066×10⁻²³×0.0066×719407.5)/(2×8.31451)
E = 1182.66×10⁻²³ J
E = 1.18266×10⁻²⁰ J
