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3 years ago

Which device is used to measure interior diameter of a water pipe and in which units are the callibrations

Physics

2 answers:

Rzqust [24]3 years ago

7 0

Answer:

The instrument is  micrometer screw gauge .

Units : millimetres

Explanation:

$.$

ahrayia [7]3 years ago

3 0

We can use a vernier calliper

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3 years ago

Read 2 more answers

Rod AB has a diameter of 200mm and rod BC has a diameter of 150mm. Find the required temperature increase to close the gap at C.

Leni [432]

Answer:

$T&=\frac{\sigma_{AB}+\sigma_{BC}}{2\alpha E}$

Explanation:

The given data :-

Diameter of rod AB ( d₁ ) = 200 mm.

Diameter of rod BC ( d₂ ) = 150 mm.

The linear co-efficient of thermal expansion of copper ( ∝ ) = 1.6 × 10⁻⁶ /°C

The young's modulus of elasticity of copper ( E ) = 120 GPa = 120 × 10³ MPa.
Consider the required temperature increase to close the gap at C = T °C
Consider the change in length of the rod = бL

Solution :-

$\begin{aligned}\sum H& =0\\-R_A+R_C&=0\\R_A&=R_C\\R_A&=R\\R_C&=R\\R_{A}&=\text{reaction\:force\:at\:A}\\R_{C}&=\text{reaction\:force\:at\:C}\\\sigma_{AB}&=\text{axial\:stress\:at\:A}\\\sigma_{BC}&=\text{axial\:stress\:at\:B}\\\sigma_{AB}&=\frac{R}{A_{A}}\\&=\frac{R_{A}}{A_{A}}\\\sigma_{BC}&=\frac{R_{B}}{A_{B}}\\&=\frac{R}{A_{B}}\\\frac{\sigma_{AB}}{\sigma_{BC}}&=\frac{A_{B}}{A_{B}}\\&=\frac{\frac{\pi}{4}\cdot 150^{2}}{\frac{\pi}{4}\cdot 200^{2}}\\&=\frac{9}{16}\end{aligned}$

$\begin{aligned}\delta L&= (\delta L _{thermal} +\delta L_{axial})_{AB} + ( \delta L _{thermal} +\delta L_{axial})_{BC}\\0& = (\delta L _{thermal} +\delta L_{axial})_{AB} + ( \delta L _{thermal} +\delta L_{axial})_{BC}\\&=\left[\alpha\:T\:L+\left(\frac{-RL}{AE}\right)\right]_{AB}+\left[\alpha\:T\:L+\left(\frac{-RL}{AE}\right)\right]_{BC}\\&=2\:\alpha\:T\:L-\frac{L}{E}(\sigma_{AB}+\sigma_{BC})\\T&=\frac{\sigma_{AB}+\sigma_{BC}}{2\alpha E}\end{aligned}$

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3 years ago

1) Calculate the potential energy of a 5.00 kg object sitting on a 3.00 meter high ledge.

maria [59]

Answer:

15kg

Explanation:

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3 years ago

Lee has a mass of 40.0 kg and ice skates with a speed of 4.6 m/s.

faltersainse [42]

Their common speed is 1.53 m/s.

<h3>What is speed?</h3>

Speed can be defined as the ratio of the distance to the time of a body in motion.

To calculate their final speed, we use the formula below.

Formula:

mu+m'u' = V(m+m')............. Equation 1

Where:

m = mass of the Lee
m' = mass of Mat
u = initial speed of Lee
u' = initial speed of Mat
V = Their common speed.

make V the subject of the equation

V = (mu+m'u')/(m+m')........... Equation 2

From the question,

Given:

m = 40 kg
m' = 80 kg
u = 4.6 m/s
u' = 0 m/s

Substitute these values into equation 2

V = [(40×4.6)+(80×0)]/(40+80)
V = 184/120
V = 1.53 m/s.

Hence, Their common speed is 1.53 m/s.

Learn more about speed here: brainly.com/question/3004254

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2 years ago

Which device is used to measure interior diameter of a water pipe and in which units are the callibrations​

Which device is used to measure interior diameter of a water pipe and in which units are the callibrations