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4 years ago

8

ASAP! What examples of resources can you give that can be classified as both material resources and energy resources? if u answe

r i'll give u a thanks

1 answer:

natulia [17]4 years ago

4 0

Wood because it is natural and we use it for furniture but we also burn it for energy.

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All stars go through a lifecycle.

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Mira is much bigger than the Sun.

Only very massive stars will go through a supernova stage, causing the outer layer to explode away and the core to collapse in on itself, becoming very dense.

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2 years ago

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the nuciel of all atoms are made of which subatomic particles A. electrons and protons B. protons and neutrons c. protons neutro

marshall27 [118]

B Protons and neutrons. Electrons are outside the nucleus.

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3 years ago

A space capsule having a mass of 9.0×10^2 kg is projected vertically upwards from the Earth’s surface with an initial kinetic en

Setler [38]

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sg

Explanation:

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3 years ago

Two identical small charged spheres are a certain distance apart, and each initially experiences an electrostatic force of magni

Rom4ik [11]

Answer:

New force, $F'=\dfrac{1}{4}F$

Explanation:

The electrostatic force between two spheres is given by :

$F=\dfrac{kq_1q_2}{r^2}$

According to given condition, each of the spheres has lost half its initial charge, new force is given by :

$F'=\dfrac{kq_1/2q_2/2}{r^2}$

$F'=\dfrac{1}{4}\times \dfrac{kq_1q_2}{r^2}$

$F'=\dfrac{1}{4}F$

So, the new force becomes (1/4)th of the initial force. Hence, the correct option is (d).

4 0

4 years ago

In the Olympic shotput event, an athlete throws the shot with an initial speed of 13.0 m/s at a 47.0° angle from the horizontal.

MariettaO [177]

Answer:

18.7 m

Explanation:

$v_{o}$ = initial speed of the shot = 13 m/s

θ = angle of launch from the horizontal = 47 deg

Consider the motion along the vertical direction

$v_{oy}$ = initial velocity along vertical direction = 13 Sin47 = 9.5 m/s

$a_{y}$ = acceleration along the vertical direction = - 9.8 m/s²

y = vertical displacement = - 1.80 m

t = time of travel

Using the kinematics equation

$y=v_{oy} t+(0.5)a_{y} t^{2}$

- 1.80 = (9.5) t + (0.5) (- 9.8) t²

t = 2.11 s

Consider the motion along the horizontal direction

x = horizontal displacement of the shot

$v_{ox}$ = initial velocity along horizontal direction = 13 Cos47 = 8.87 m/s

$a_{x}$ = acceleration along the horizontal direction = 0 m/s²

t = time of travel = 2.11 s

Using the kinematics equation

$x=v_{ox} t+(0.5)a_{x} t^{2}$

x = (8.87) (2.11) + (0.5) (0) (2.11)²

x = 18.7 m

8 0

3 years ago