Ask question

Ask question

All categories

3 years ago

8

ASAP! What examples of resources can you give that can be classified as both material resources and energy resources? if u answe

r i'll give u a thanks

1 answer:

natulia [17]3 years ago

4 0

Wood because it is natural and we use it for furniture but we also burn it for energy.

You might be interested in

What makes the north star, polaris, special?

Mama L [17]

It's the only star in the sky (visible from the northern hemisphere) that never seems to move. It stays at almost exactly the same point in the sky, while the other stars all circle around it once a day.

7 0

3 years ago

EASY BRAINLIEST PLEASE HELP!!

jeka94

Answer:

Solution given:

frequency[f]=60,500,000Hz

velocity[V]=300,000,000m/s

wave length=?

we have

wave length= $\frac{V}{f}$

= $\frac{300,000,000}{60,500,000}$

= $\frac{3000}{605}$ =4.96 m

Option A.4.96m

3 0

3 years ago

Read 2 more answers

A solenoid having N turns and carrying a current of 2.000 A has a length of 34 00 cm. If the magnitude of the magnetic field gen

umka21 [38]

Answer:

B) 1218

Explanation:

N = Total number of turns in the solenoid

L = length of the solenoid = 34.00 cm = 0.34 m

B = magnetic field at the center of the solenoid = 9 mT = 9 x 10⁻³ T

i = current carried by the solenoid = 2.000 A

Magnetic field at the center of the solenoid is given as

$B = \frac{\mu _{o}N i}{L}$

$9\times 10^{-3} = \frac{(4\pi\times 10^{-7} )N (2)}{0.34}$

N = 1218

3 0

3 years ago

Read 2 more answers

In order for convection to transfer heat, particles need to

Sergio [31]

Answer:

the answer is b mark me as the brqinlist

7 0

2 years ago

Read 2 more answers

Suppose that a comet that was seen in 563 A.D. by Chinese astronomers was spotted again in year 1951. Assume the time between ob

Mars2501 [29]

Answer:

$a=2.77*10^{13}m$

$R_a=5.49*10^{13}m$

Explanation:

The period of the comet is the time it takes to do a complete orbit:

T=1951-(-563)=2514 years

writen in seconds:

$2514years*\frac{3,154*10^7s}{1year}=7.93 *10^{10}s$

Since the eccentricity is greater than 0 but lower than 1 you can know that the trajectory is an ellipse.

Therefore, if the mass of the sun is aprox. 1.99e30 kg, and you assume it to be much larger than the mass of the comet, you can use Kepler's law of periods to calculate the semimajor axis:

$T^2=\frac{4\pi^2}{Gm_{sun}}a^3\\ a=\sqrt[3]{\frac{Gm_{sun}T^2}{4\pi^2} } \\a=1.50*10^{6}m$

Then, using the law of orbits, you can calculate the greatest distance from the sun, which is called aphelion:

$R_a=a(1+e)\\R_a=2.77*10^{13}(1.986)\\R_a=5.49*10^{13}m$

8 0

2 years ago