1)what is the momentum of a 40,000,000kg tanker traveling at 5 m/s?

7) T F If two forces of equal magnitude act on an object that is hinged at a pivot, the force acting farther from the pivot must

saul85 [17]

Answer:

False

Explanation:

The torque exerted by a force is given by:

$\tau=Fd sin \theta$

where

F is the magnitude of the force

d is the distance between the point of application of the force and the pivot

$\theta$ is the angle between the directions of F and d

We see that the magnitude of the torque depends on 3 factors. In this problem, we have 2 forces of equal magnitude (so, equal F). Moreover, one of the forces (let's call it force 1) acts farther from the pivot than force 2, so we have

$d_1 > d_2$

However, this does not mean that force 1 produces a greater torque. In fact, it also depends on the angle at which the force is applied. For instance, if the first force is applied parallel to d, then we have

$\theta_1 =0\\sin \theta=0$

and the torque produced by this force would be zero.

So, the statement is false.

4 0

3 years ago

X-rays with an energy of 86 keV scatter off of stationary electrons. How much energy do the photons scattering at 60° have? A. 7

AveGali [126]

Answer:

A. 79.3 keV

Explanation:

Because the procedure involves many steps for its resolution and it works faster on paper and pencil, the detailed solution of this exercise is attached as a scanned image of the procedure for review.

In the procedure, the initial values of the problem and the replacement of these values with the correct formulas for this process are taken into account.

7 0

3 years ago

Calculate the ratio of the resistance of 12.0 m of aluminum wire 2.5 mm in diameter, to 30.0 m of copper wire 1.6 mm in diameter

alukav5142 [94]

Answer: 0.258

Explanation:

The resistance $R$ of a wire is calculated by the following formula:

$R=\rho\frac{l}{s}$ (1)

Where:

$\rho$ is the resistivity of the material the wire is made of. For aluminium is $\rho_{Al}=2.65(10)^{-8}m\Omega$ and for copper is $\rho_{Cu}=1.68(10)^{-8}m\Omega$