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4 years ago

15

Use the periodic table to complete the equation that represents the process of nuclear fusion. Superscript 14 Subscript 7 Baseli

ne N + Superscript 1 Subscript 1 Baseline H yields Superscript A Subscript B Baseline C

2 answers:

klemol [59]4 years ago

8 0

Answer:

A: 15

B: 8

C: O

Explanation:

polet [3.4K]4 years ago

6 0

Answer:

A:15

B:8

C: O

Explanation:

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A machine carries a 100kg cargo to a boat at a rate of 10m/s2. The distance between the ground to the boat is 50ft. If the machi

klasskru [66]

Answer:

50.8 watt

Explanation:

we know that P=W÷t

W=F.S S-->distance=50 ft= 15.24 m

F=ma

=100×10=1000 N

SO W= 1000×15.24

=15240 J

NOW

P=W÷t t=5 mints = 5×60=300 sec

P=15240÷300

P=50.8 watt

8 0

3 years ago

Compare the de Broglie wavelength of a golf ball moving at 70.0 miles per hour (31.3 m/s) to that of an alpha particle moving at

sergiy2304 [10]

Answer:

1. Golf ball is in the range of only particulate detectable range

2, alpha partcle is in ultraviolet range of wavelength

3.bullet is in xray range of wavelength

All in the EMW spectrum

6 0

3 years ago

xxMikexx [17]

Answer:

The principle of momentum conservation states that if there no external force the total momentum of the system before and after the collision is conserved.

Since momentum is a vector, we should investigate the directions and magnitudes of initial and final momentum.

$\vec{P}_{initial} = \vec{P}_{final}\\\vec{P}_{initial} = m_1\vec{v}_1 + 0\\\vec{P}_{final} = m_1\vec{v}_1' + m_2 \vec{v}_2'$

If the first ball hits the second ball with an angle, we should separate the x- and y-components of the momentum (or velocity), and apply conservation of momentum separately on x- and y-directions.

6 0

3 years ago

Three-fourths of the elements on the

77julia77 [94]

Answer:

b

Explanation:

because the metalloids are the thing in the middle

8 0

3 years ago

2) Two railway tracks are parallel to west east direction. Along one track, train A moves with a speed of 45 m/s from

Natalija [7]

Answer:

105 m/s

Explanation:

Given that the speed of train A, $V_A$ = 45 m/s from west to east.

Speed of train B, $V_B$ = 60 m/s from east to west.

Train B is moving in the opposite direction with respect to the speed of train A. Assuming that the speed from east to west direction is positive.

So, the speed of train A from east to west= - 45 m/s

The speed of train B w.r.t train A $= V_B - V_A=60-(-45)=60+45=105$ m/s

Hence, the speed of train B w.r.t train A is 105 m/s from east to west.

5 0

3 years ago