A loop circuit has a resistance of R1 and a current of 2 A. The current is reduced to 1.5 A when an additional 1.6 Ω resistor is
2 answers:
Answer:
R1 = 4.8Ω
Explanation:
The loop circuit has an initial voltage of V = IR
I = 2 A , R1 = R
V = 2R1
with the current reduced to 1.5A with an additional 1.6Ω resistor
the total resistance of the circuit is 1.6 + R1
the voltage of the two scenarios has to be equal , since the same voltage flows through the circuit
therefore V = 2R1
from Ohms law V = IR
2R1= 1.5 (1.6 + R1)
2R1 = 2.4 + 1.5R1
collecting like terms
2R1 - 1.5R1 = 2.4
0.5R1 = 2.4
R1 =
R1 = 4.8Ω
You might be interested in
Answer:
Part a)
Part b)
Part c)
Explanation:
Part a)
As we know that force on the passenger while moving in circle is given as
now variation in force is given as
here speed is constant
Part b)
Now if the variation in force is required such that r is constant then we will have
so we have
Part c)
As we know that time period of the circular motion is given as
so here if radius is constant then variation in time period is given as
The final temperature of the system will be equal to the initial temperature, and which is 373K. The work done by the system is 409.8R Joules.
To find the answer, we need to know about the thermodynamic processes.
<h3>How to find the final temperature of the gas?</h3>- Any processes which produce change in the thermodynamic coordinates of a system is called thermodynamic processes.
- In the question, it is given that, the tank is rigid and non-conducting, thus, dQ=0.
- The membrane is raptured without applying any external force, thus, dW=0.
- We have the first law of thermodynamic expression as,
- Here it is zero.
,
- As we know that,
- Thus, the final temperature of the system will be equal to the initial temperature,
- We found that the process is isothermal,
- Thus, the work done will be,
Where, R is the universal gas constant.
<h3>What is a reversible process?</h3>- Any process which can be made to proceed in the reverse direction is called reversible process.
- During which, the system passes through exactly the same states as in the direct process.
Thus, we can conclude that, the final temperature of the system will be equal to the initial temperature, and which is 373K. The work done by the system is 409.8R Joules.
Learn more about thermodynamic processes here:
#SPJ1