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kondaur [170]
4 years ago
9

75 points for this, please take the challenge

Chemistry
1 answer:
beks73 [17]4 years ago
3 0

Answer:

The answer is contained in the attachment.

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Which substance is a reducing agent?<br><br> A. CO<br> B. F2<br> C. CO2<br> D. H2O2<br> E. FeSO4
IRISSAK [1]

H2O2

\mathtt \red{Hope \:  it  \: helps}

6 0
3 years ago
Read 2 more answers
Given 8.25 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100
mash [69]

Answer:

              10.87 g of Ethyl Butyrate

Solution:

The Balance Chemical Equation is as follow,

   H₃C-CH₂-CH₂-COOH + H₃C-CH₂-OH  →  H₃C-CH₂-CH₂-COO-CH₂-CH₃ + H₂O

According to equation,

    88.11 g (1 mol) Butanoic Acid produces  =  116.16 g (1 mol) Ethyl Butyrate

So,

           8.25 g Butanoic Acid will produce  =  X g of Ethyl Butyrate

Solving for X,

                      X =  (8.25 g × 116.16 g) ÷ 88.11 g

                      X =  10.87 g of Ethyl Butyrate

8 0
3 years ago
A sample of an unknown gas effuses in 14.4 min. An equal volume of H2 in the same apparatus under the same conditions effuses in
Elena-2011 [213]

Answer:- molar mass of the unknown gas is 71.5 gram per mol.

Solution:- From Graham's law of effusion rates, the rate of effusion of a gas is inversely proportional to the square root of it's molar mass.

When we compare the effusion rates of two gases then the formula for Graham's law is:

\frac{rate_1}{rate_2}=\sqrt{\frac{M_2}{M_1}}

In this formula, V stands for volume and M stands for molar mass

Rate is volume effused per unit time. Since, the volumes are same, the formula could be written as:

\frac{t_2}{t_1}=\sqrt{\frac{M_2}{M_1}}

let's say in formula, subscript 1 is for hydrogen gas and 2 is for the unknown gas.

Molar mass of hydrogen is 2.02 grams per mol and the time taken to effuse it is 2.42 min. The time taken to effuse the unknown gas is 14.4 min and we are asked to calculate it's molar mass. let's plug in the values in the formula:

\frac{14.4}{2.42}=\sqrt{\frac{M_2}{2.02}}

5.95=\sqrt{\frac{M_2}{2.02}}

doing squares to both sides:

35.4=\frac{M_2}{2.02}

M_2=35.4*2.02

M_2=71.5

So, the molar mass of the unknown gas is 71.5 grams per mol.



4 0
3 years ago
What is the correct value using 3 significant figures for 14.8232 g/mol?
REY [17]

Answer:

14.8 g/mol

Explanation:

Starting on the left, count in 3 numbers (14.8), then round using the next number (0.02).

Because 2 is less than 5, the number stays the same and is not rounded up.

5 0
4 years ago
At what temperature does water evaporate?
Alexus [3.1K]
It evaporates at 100°
4 0
3 years ago
Read 2 more answers
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