All categories

4 years ago

Acids add ______ ions to a solution. A. H+ B. OH+ C. OH- D. H-

Chemistry

2 answers:

mamaluj [8]4 years ago

8 0

Answer: A)H+

Explanation:my teacher just told me

Elza [17]4 years ago

4 0

Answer:

H+ Ions

Explanation:

Answer for Educere/ Founder's Education

You might be interested in

A solution is made by mixing equal masses of methanol, CH 4 O , CH4O, and ethanol, C 2 H 6 O . C2H6O. Determine the mole fractio

wariber [46]

Answer: The mole fraction of methanol

Xmeth= 0.59

The mole fraction of ethanol

Xeth = 0.41

Explanation:

Mole fraction of a component can be determined by:

Xi = moles of i / total moles of the components the components

Where i indicates the component

An equal mass of 100.0g is assumed for both methanol and ethanol

Molar mass of Methanol (CH4O)

= (1*12) + (4*1) +(1*16) =32g/mol

Mole of Methanol = mass of methanol /molar mass of methanol

=100/32 = 3.13mol.

Molar mass of ethanol ( C2H6O)

= (2*12)+(6*1)+(1*16) = 46.0g/mol

Mole of ethanol = 100/46

= 2.17mol.

Mole fraction of methanol (Xmeth)

= moles of methanol / total moles

Xmeth = 3.13/(3.13+2.17)

Xmeth = 0.59

Mole fraction of ethanol (Xeth)

= moles of ethanol /total moles

= 2.17/((3.13+2.17)

Xeth= 0.41

5 0

3 years ago

The standard cell potential Ec for the reduction of silver ions with elemental copper is 0.46V at 25 degrees celsius. calculate

Cloud [144]

Answer : The $\Delta G$ for this reaction is, -88780 J/mole.

Solution :

The balanced cell reaction will be,

$Cu(s)+2Ag^+(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)$

Here, magnesium (Cu) undergoes oxidation by loss of electrons, thus act as anode. silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.

The half oxidation-reduction reaction will be :

Oxidation : $Cu\rightarrow Cu^{2+}+2e^-$

Reduction : $2Ag^++2e^-\rightarrow 2Ag$

Now we have to calculate the Gibbs free energy.

Formula used :

$\Delta G^o=-nFE^o$

where,

$\Delta G^o$ = Gibbs free energy = ?

n = number of electrons to balance the reaction = 2

F = Faraday constant = 96500 C/mole

$E^o$ = standard e.m.f of cell = 0.46 V

Now put all the given values in this formula, we get the Gibbs free energy.

$\Delta G^o=-(2\times 96500\times 0.46)=-88780J/mole$

Therefore, the $\Delta G$ for this reaction is, -88780 J/mole.

7 0

4 years ago

How many moles of gas sample are 5.0 L container at 373K and 203kPa

Rom4ik [11]

For the purpose we will here use the ideal gas law:

p×V=n×R×T

V= 5.0 L

T= 373K

p= 203kPa

R is universal gas constant, and its value is 8.314 J/mol×K

Now when we have all necessary date we can calculate the number of moles:

n=p×V/R×T

n= 203 x 5 / 8.314 x 373 = 0.33 mole

6 0

4 years ago

Hybridization of - C=CH , it should be 3 triple bonds?

dimulka [17.4K]

It is an sp hybridization

5 0

4 years ago

In a particular breed of cattle a black coat is dominant over a red coat if a cow with the red coat is crossed with the black ba

Furkat [3]

It's D because a dominant Gene will take over a recessive

4 0

3 years ago