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GREYUIT [131]
2 years ago
7

If a chocolate bar has 270 Calories from fat, does this mean the chocolate bar has 15 or 30. grams of fat? Explain.

Chemistry
2 answers:
Nostrana [21]2 years ago
8 0

<u>Answer:</u>

<em>The chocolate bar has 30 grams of fat, if it has 270 fat calories. </em>

<u>Explanation:</u>

Nourishment calories are characterized as the measure of warmth vitality required to raise the temperature of one kilogram of water by one degree Celsius.

The micro nutrients in our nourishment like proteins, fats and starches has their particular commitment to the absolute nourishment calorie which was taken by the human.

It is realized that every gram of fat adds to 9 calories in any nourishment thing.

1 g of Fat= 9 fat calories

1 fat calories= 19 g of fat

270 fat calories= 270 \times 19g of fat = 30 g of fat

Thus 270 fat calories will contain 30 g of fat in it.

maksim [4K]2 years ago
7 0

Answer:

30

Explanation:

Each gram of fat has 9 calories, knowing that:

fat=\frac{270[cal]}{9\frac{cal}{g} } =30[g]

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3 years ago
Ammonia (nh3) is widely used as a fertilizer and in many household cleaners. how much ammonia is produced when 6.64 mol of hydro
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5 0
2 years ago
The town of Natrium, West Virginia, derives its name from the sodium produced in the electrolysis of molten sodium chloride (NaC
Alona [7]

Explanation:

The reaction equation will be as follows.

           Na^{+} + e^{-} \rightarrow Na(s)

Hence, moles of Na = moles of electron used

Therefore, calculate the number of moles of sodium as follows.

       No. of moles = \frac{mass}{\text{molar mass}}

                             = \frac{4500 g}{23 g/mol}    (as 1 kg = 1000 g)

                             = 195.65 mol

As,     Q = n \times F       where F = Faraday's constant

              = 195.65 mol \times 96500 C

              = 1.88 \times 10^{7} mol C

Relation between electrical energy and Q is as follows.

               E = Q \times V

Hence, putting the given values into the above formula and then calculate the value of electricity as follows.

              E = Q \times V

                 = 1.88 \times 10^{7} \times 5

                 = 9.4 \times 10^{7} J

As 1 J = 2.77 \times 10^{-7} kWh

Hence,      \frac{9.4 \times 10^{7}}{2.77 \times 10^{-7}} kWh

                = 3.39 kWh

Thus, we can conclude that 3.39 kilowatt-hours of electricity is required in the given situation.

7 0
3 years ago
Read 2 more answers
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