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Snezhnost [94]
2 years ago
15

A 0.0780 kg lemming runs off a

Physics
1 answer:
kotegsom [21]2 years ago
4 0

Answer:

5.01 J

Explanation:

Info given:

mass (m) = 0.0780kg

height (h) = 5.36m

velocity (v) = 4.84 m/s

gravity (g) = 9.81m/s^2

1. First, solve for Kinetic energy (KE)

KE = 1/2mv^2

1/2(0.0780kg)(4.84m/s)^2 = 0.91 J

so KE = 0.91 J

2. Next, solve for Potential energy (PE)

PE = mgh

(0.0780kg)(9.81m/s^2)(5.36m) = 4.10 J

so PE = 4.10 J

3. Mechanical Energy , E = KE + PE

Plug in values for KE and PE

KE + PE = 0.91J + 4.10 J = 5.01 J

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Explanation:

A parachutist of mass 56.0 kg jumps out of a balloon at a height of 1400 m and lands on the ground with a speed of 5.10 m/s. How much energy was lost to air friction during this bump

The energy lost due to friction is expressed using the formula;

Energy lost  = Potential Energy + Kinetic Energy

Energy lost  = mgh + 1/2mv²

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Substitute the given values into the formula;

Energy lost  = 56(9.8)(1400) + 1/2(56)(5.10)²

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<em>Hence the amount of energy that was lost to air friction during this jump is 769,048.28Joules</em>

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2 years ago
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Alex_Xolod [135]

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all I got

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3 years ago
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Nana76 [90]

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Using these identities:
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We can cancel out cos <span>θ, leaving us with
</span>cot θ ∙ sec θ = 1 / sin θ
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