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2 years ago

A 0.0780 kg lemming runs off a

Physics

1 answer:

kotegsom [21]2 years ago

4 0

Answer:

5.01 J

Explanation:

Info given:

mass (m) = 0.0780kg

height (h) = 5.36m

velocity (v) = 4.84 m/s

gravity (g) = 9.81m/s^2

1. First, solve for Kinetic energy (KE)

KE = 1/2mv^2

1/2(0.0780kg)(4.84m/s)^2 = 0.91 J

so KE = 0.91 J

2. Next, solve for Potential energy (PE)

PE = mgh

(0.0780kg)(9.81m/s^2)(5.36m) = 4.10 J

so PE = 4.10 J

3. Mechanical Energy , E = KE + PE

Plug in values for KE and PE

KE + PE = 0.91J + 4.10 J = 5.01 J

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Betty (mass 40 kg), standing on slippery ice, catches her leaping dog (mass 15 kg) moving horizontally at 3.0 m/s. Show that the

MA_775_DIABLO [31]

Answer:

v = 2.18m/s

Explanation:

In order to calculate the speed of Betty and her dog you take into account the law of momentum conservation. The total momentum before Betty catches her dog must be equal to the total momentum after.

Then you have:

$Mv_{1o}+mv_{2o}=(M+m)v$ (1)

M: mass Betty = 40kg

m: mass of the dog = 15kg

v1o: initial speed of Betty = 3.0m/s

v2o: initial speed of the dog = 0 m/s

v: speed of both Betty and her dog = ?

You solve the equation (1) for v:

$v=\frac{Mv_{1o}+mv_{2o}}{M+m}=\frac{(40kg)(3.0m/s)+(15kg)(0m/s)}{40kg+15kg}\\\\v=2.18m/s$

The speed fo both Betty and her dog is 2.18m/s

7 0

2 years ago

I NEED HELP PLEASE, THANKS! :)

UkoKoshka [18]

Answer:

Explanation:

1) Hypermetropia (better known as Farsighted- this is why nearby objects seem blurry for him)

2) In such instances, image are typically formed farther from the near point

3) Such defects are quite common so there are common procedures such as using convex lens which can restore the sight to normal.

7 0

2 years ago

What is the weight of a dog with a mass of 12 kg? Explain how you obtained your answer.

butalik [34]

Answer: 117.60N

Explanation:

Weight is a force. Therefore, we can use the force formula to find weight.

$Formula: W=m*g$

W = weight

m = mass

g = acceleration due to gravity ( $9.8m/s^2$ )

$W=(12kg)(9.8m/s^2)\\W=117.60N$

5 0

3 years ago

Read 2 more answers

a car moving east at 45 km/h turns and travels west at 30 km/h. What is the magnitude and direction of the change in velocity?

PSYCHO15rus [73]

Magnitude of change is 15km/h
change in direction is to the right?

3 0

3 years ago

Read 2 more answers

HELP PLEASE

-BARSIC- [3]

Angel ! You have a formula, and you have an example that's
completely worked out. The ONLY POSSIBLE reason that you
could still need help is that you're letting math scare you.

I'll do 'A' for you, 'B' most of the way, and get 'C' set up.
If THAT's not enough for you to run with and finish them all,
then you and I should both be embarrassed.

Write the formula on the wall:

   °F = (9/5) °C + 32°

A). Convert 35° C °F = (9/5)(35°) + 32°

(9/5)(35) = 63 °F = 63° + 32°

   °F = 95°
____________________________________

B). Convert 80°F to °C
       The formula: °F = (9/5) °C + 32°

°F = 80    80 = (9/5)°C + 32

Subtract 32 from each side: 48 = (9/5)°C

Multiply each side by 5 : 240 = (9) C

Now you take over:
_________________________________________

C). Convert 15°C to °F.
       The formula: °F = (9/5) °C + 32°

°C = 15 °F = (9/5) 15° + 32

(9/5) (15) = 27
   Go !    °F =

7 0

3 years ago