Answer:
KE = 2.535 x 10⁷ Joules
Explanation:
given,
angular speed of the fly wheel = 940 rad/s
mass of the cylinder = 630 Kg
radius = 1.35 m
KE of flywheel = ?
moment of inertia of the cylinder
=
= 574 kg m²
kinetic energy of the fly wheel
KE = 2.535 x 10⁷ Joules
the kinetic energy of the flywheel is equal to KE = 2.535 x 10⁷ Joules
Answer:
The period is
Explanation:
From the question we are told that
The mass is
The extension of the spring is
The spring constant for this is mathematically represented as
Where F is the force on the spring which is mathematically evaluated as
So
The period of oscillation is mathematically evaluated as
substituting values