Question

A solution contains 10.6 g of glucose. How many moles of glucose are present? How many molecules of glucose are present? How many carbon atoms are there within the glucose molecules

Answer 1

Answer:

- $moles=0.0588mol\ Glucose$

- $molecules=3.54x10^{22} molecules \ Glucose$

- $atoms \ C=2.13x10^{23}atoms \ C$

Explanation:

Hello,

In this case, by knowing molar mass of glucose is 180.156 g/mol, we can apply the following mole-mass-particles relationships in order to compute the moles, molecules and carbon atoms in the 10.6-g sample of glucose:

- Moles:

$moles=10.6g\ Glucose*\frac{1mol\ Glucose}{180.156g\ Glucose}\\\\moles=0.0588mol\ Glucose$

- Molecules: we also use Avogadro's number.

$molecules=10.6g\ Glucose*\frac{1mol\ Glucose}{180.156g\ Glucose}*\frac{6.022x10^{23} molecules \ Glucose}{1mol\ Glucose} \\\\molecules=3.54x10^{22} molecules \ Glucose$

- Carbon atoms: here, particularly, one mole of glucose has six moles of carbon atoms, thus:

$atoms\ C=10.6g\ Glucose*\frac{1mol\ Glucose}{180.156g\ Glucose}*\frac{6molC}{1mol\ Glucose} *\frac{6.022x10^{23}atoms \ C}{1molC} \\\\atoms \ C=2.13x10^{23}atoms \ C$

Regards.