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zhuklara [117]
3 years ago
11

Assume the cup of tea has cooled off faster than the pot of tea. In which liquid would the molecules be moving faster and in whi

ch would they be moving slower?
Chemistry
2 answers:
OLga [1]3 years ago
8 0
In the pot of tea the molecules would be moving faster than in the cooled cup of tea. As liquid is heated the atoms vibrate faster which increases the distance between them. When heat leaves a substance, the molecules vibrate slower and get closer.
Serjik [45]3 years ago
5 0
In the pot of tea the molecules would be moving faster than the tea in the cup.

So when the liquid heats up the molecules vibrate fast and it increases the difference between them. When the heat leaves a substance, the molecules vibrate slower and get closer.

Hope I Helped You!!! :-)

<span>Have A Good Day!!!</span>
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What is the most striking part of this simulation?
oee [108]
None of the alpha particles fired at the foil are being repelled back, like they were in the Rutherford atom simulation.I hope this correct.

3 0
3 years ago
Why are alkalis sometimes<br> described as the opposite of<br> acids?
zlopas [31]

Answer: Because Alkalis are bases that can dissolve in water, which can also neutralize acid.

7 0
3 years ago
Methyl salicylate is a common active ingredient in liniments such as ben-gay. It is also known as oil of wintergreen. It is made
arlik [135]

Answer: The empirical formula is C_3H_3O.

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2 = 12.24 g

Mass of H_2O = 2.505 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 12.24 g of carbon dioxide, =\frac{12}{44}\times 12.24=3.338g of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 2.505 g of water, =\frac{2}{18}\times 2.505=0.278g of hydrogen will be contained.

Mass of oxygen in the compound = (5.287) - (3.338+0.278) = 1.671  g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{3.338g}{12g/mole}=0.278moles

Moles of H=\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.278g}{1g/mole}=0.278moles

Moles of O=\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{1.671g}{16g/mole}=0.104moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =\frac{0.278}{0.104}=3

For H =\frac{0.278}{0.104}=3

For O =\frac{0.104}{0.104}=1

The ratio of C : H : O = 3: 3: 1

Hence the empirical formula is C_3H_3O.

5 0
3 years ago
The statement “the scientific process is open ended” means:
mina [271]

Answer:

think it helps you

<h2>Explanation:</h2>

<em><u>The statement “the scientific process is open ended” means: Would an element with 7 valence electrons be more or less reactive than an element with 3 valence electrons? Element 1 is a hard dark-red solid</u></em>

4 0
3 years ago
What is the bond dissociation energy for breaking all the bonds in a mole of o2 molecules?
djverab [1.8K]
<h3>Answer:</h3>

498 kj/mol

<h3>Explanation:</h3>
  • Chemical reactions occur as a result of bond breaking and bond formation.
  • The bonds in reactants are broken and atoms are rearranged to form new bonds.
  • During bond breaking energy is absorbed to break the bonds of reactants while bond formation involves the release of energy during the formation of new bonds.

In our case;

In 1 mole of the Oxygen molecule, there is one O=O bond

Energy absorbed to break O=O is 498 kJ/mol

Therefore, the ΔH required to break all the bonds in one mole of Oxygen(O₂) molecules is 498kJ/mol.

Note that, bond breaking is endothermic since energy is absorbed  from the surroundings.

8 0
3 years ago
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