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Kay [80]
3 years ago
10

The substances below are listed by increasing specific heat capacity value. Starting at 30.0 °C, they each absorb 100 kJ of ther

mal energy. Which one do you expect to increase in temperature the most? Silver, 0.239 J/(g °C) Aluminum, 0.921 J/(g °C) Lithium, 3.56 J/(g °C) Water, 4.184 J/(g °C)
Chemistry
1 answer:
timama [110]3 years ago
7 0

Answer:

Silver, 0.239 J/(g °C)

Explanation:

  • The heat change is related to specific heat as given by the formula;

Heat change = mass of substance × specific heat × change in temperature

  • Therefore; considering same amount of substance or equal masses and have the same initial temperature.
  • The change in temperature will be inversely proportional to the specific heat.
  • Therefore; the higher the specific heat lower the temperature change.
  • Hence,  the change in temperature will be highest for the substance with the lowest specific heat.

Therefore; the one that will increase in temperature the most is Silver

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2 years ago
A sample of gas is held at 100oc at a volume of 20 L.if the volume is increased to 40 L what is the new temperature of the gas i
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Answer:

470 °C  

Explanation:

This looks like a case where we can use Charles’ Law:  

\dfrac{V_{1}}{T_{1}} =\dfrac{V_{2}}{T_{2}}

Data:

V₁ = 20 L; T₁ = 100 °C

V₂ = 40 L; T₂ = ?  

Calculations:

(a) Convert the temperature to kelvins

T₁ = (100 + 273.15) K = 373.15 K

(b) Calculate the new temperature

\begin{array}{rcl}\dfrac{V_{1}}{T_{1}}& =&\dfrac{V_{2}}{T_{2}}\\\\ \dfrac{\text{20 L}}{\text{373.15 K}} &=&\dfrac{\text{40 L}}{T_{2}}\\\\{\text{15 000 K}} & = & 20T_{2}\\T_{2} & = &\dfrac{\text{15 000 K}}{20 }\\\\T_{2} & = & \textbf{750 K}\\\end{array}

Note: The answer can have only two significant figures because that is all you gave for the volumes.

(c) Convert the temperature to Celsius

T₂ = (750 – 273.15) °C = 470 °C

3 0
3 years ago
Difference between fission and fusion?
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3 years ago
A galvanic cell consists of a Al3 /Al half-cell and a standard hydrogen electrode. If the Al3 /Al half-cell standard cell functi
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Answer:

Explanation:

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3 0
3 years ago
A scientist measures the standard enthalpy change for the following reaction to be -327.2 kJ : P4O10(s) 6 H2O(l)4H3PO4(aq) Based
OleMash [197]

Answer:

ΔH°f P4O10(s) = - 3115.795 KJ/mol

Explanation:

  • P4O10(s) + 6H2O(l) ↔ 4H3PO4(aq)
  • ΔH°rxn = ∑νiΔH°fi

∴ ΔH°rxn = - 327.2 KJ

∴ ΔH°f H2O(l) = - 285.84 KJ/mol

∴ ΔH°F H3PO4(aq) = - 1289.5088 KJ/mol

⇒ ΔH°rxn = (4)(- 1289.5088) - (6)(- 285.84) - ΔH°f P4O10(s) = - 327.2 KJ

⇒ ΔH°f P4O10(s) = - 5158.035 + 1715.04 + 327.2

⇒ ΔH°f P4O10(s) = - 3115.795 KJ/mol

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