All categories

3 years ago

What are the three main types of stress in rock

1 answer:

7 0

Compression, shearing and tension are the three main types of stresses faced by rocks. In regards to the force of compression, external force acts on the rock to squeeze it until it disintegrates. In case of shearing, the rock is pulled in two opposite directions by force. This ultimately results in the rock breaking down into pieces. Tension is another force that pulls the rock, making it thin in the middle. This way the rock disintegrates as it becomes weaker and weaker in the middle. Most of the rocks present in the earths crust are hugely affected by these three forces.

You might be interested in

Assume that a person bouncing a ball represents a closed system. Which statement best describes how the amounts of the ball's po

Zinaida [17]

Answer:

Explanation:

7 0

3 years ago

Using that transfers and third laws explain what happened when you dribble a basketball

Leno4ka [110]

The ball is using an reaction and opposite reaction, so when you dribble a basketball you push the ball with downward force and the ground pushes the ball back up thus making the opposite reaction.

5 0

3 years ago

I don’t get how to answer the questions.

Dominik [7]

Write the answer below the question?

6 0

3 years ago

A man pushes a lawn mower on a level lawn with a force of 195 N. If 37% of this force is directed downward, how much work is don

densk [106]

Answer:

$W = 1032.6 J$

Explanation:

Net force by which man push the lawn mower is given as

$F = 195 N$

now it is given that 37% of this force is vertically downwards

so we will have

$F_y = 0.37 \times 195$

$F_y = 72.15 N$

now we also know that

$F_x^2 + F_y^2 = F^2$

here we have

$F_x^2 + 72.15^2 = 195^2$

$F_x = 181.2 N$

Now work done by this force to move the lawn mower is given as

$W = F_x . d$

$W = (181.2)(5.7 m)$

$W = 1032.6 J$

7 0

3 years ago

An object is falling from a height of 7.5 meters. At what height will it’s velocity be 7 meters/second?

Nady [450]

One of the equations of gravity is this:
${v}^{2} = {u}^{2} + 2gh$
Where v = final velocity which is 7m/s
u = initial velocity which is 0 for objects falling from a height
g = acceleration due to gravity and it is approximately 10m/s^2. It's a constant so pretty much remember this number. It's positive since the work being done is caused by gravity (in other words, it's falling down). It can also be negative if the work being down is against gravity (in other words, it's going up)
h = height of object

Substitute for the values and you should have something like this
${7}^{2} = {0}^{2} + 2 \times 10 \times h$
$49 = 0 + 20h$
$h = \frac{49}{20}$
$h = 2.5m$

6 0

3 years ago