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arsen [322]
3 years ago
7

What are the three main types of stress in rock

Physics
1 answer:
Rzqust [24]3 years ago
7 0
Compression, shearing and tension are the three main types of stresses faced by rocks. In regards to the force of compression, external force acts on the rock to squeeze it until it disintegrates. In case of shearing, the rock is pulled in two opposite directions by force. This ultimately results in the rock breaking down into pieces. Tension is another force that pulls the rock, making it thin in the middle. This way the rock disintegrates as it becomes weaker and weaker in the middle. Most of the rocks present in the earths crust are hugely affected by these three forces.
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Explanation:

Attach is the solution

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3 years ago
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marusya05 [52]

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The solution and the explanation are in the Explanation section.

Explanation:

According to the diagram that is in the attached image, the EFFORT force at point A and the load is at O point. The torque due to weight is:

TA = W * (a * cosθ)

The torque due to effort at C point is:

TC = E * (b * cosθ)

The net torque is equal to 0, we have:

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8 0
3 years ago
8. Three grams of Bismuth-218 decay to 0.375 grams in one hour. What is the half-
Evgen [1.6K]

Answer: 0.333 h

Explanation:

This problem can be solved using the <u>Radioactive Half Life Formula</u>:  

A=A_{o}.2^{\frac{-t}{H}} (1)  

Where:  

A=0.375 g is the final amount of the material  

A_{o}=3 g is the initial amount of the material  

t=1 h is the time elapsed  

H is the half life of the material (the quantity we are asked to find)  

Knowing this, let's substitute the values and find h from (1):

0.375 g=(3 g)2^{\frac{-1h}{H}} (2)  

\frac{0.375 g}{3 g}=2^{\frac{-1h}{H}} (3)  

Applying natural logarithm in both sides:

ln(\frac{0.375 g}{3 g})=ln(2^{\frac{-1 h}{H}}) (4)  

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Clearing H:

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Finally:

h=0.333 h This is the half-life of the Bismuth-218 isotope

4 0
3 years ago
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