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2 years ago

True or False: A 24 year old motorcycle driver would not be required to wear protective eyewear when riding in Florida.

Physics

2 answers:

n200080 [17]2 years ago

6 0

False people should always wear gear

Alexeev081 [22]2 years ago

4 0

It is true that a 24 years old motorcycle driver would not be required to wear a protective eyewear when riding in Florida.

It is illegal for anyone to operate a motorcycle without wearing approved safety helmets in Florida, but there are few exemptions particularly for riders above the age of 21, provided they comply with the existing Florida Helmet Law.

<h2>Further Explanation</h2>

Since the law has been amended in 2011, it is now compulsory for anyone over the age of 21 to prove they are covered by $10,000 medical insurance policy before they can be exempted from operating a motorcycle without wearing a protective eyewear in Florida.

In other words, any one that is over the age of 21 can operate a motorcycle without using helmet provided they are insured. The Florida helmet is consistent with the federal safety guidelines

If you are not up to the age of 21, no matter the level of your insurance policy, you must put on helmets anytime you operate a motorcycle in Florida.

However, If you are over the age of 21 and qualified to operate without helmets, it is advisable to always carry your prove of insurance with you because law enforcement officer might request for it.

LEARN MORE:

Florida helmets law: brainly.com/question/3352598

KEYWORDS:

insurance policy
florida helmets law
riding
motorcycle rider
law enforcement

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Which is a example of application of a scientific concept?

stira [4]

I think its c or d but im not quite sure.....

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2 years ago

What force is produced when a battery causes an electric current to flow trough a circuit made of copper wire

zzz [600]

You'll hear that force called different things in different places. It
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It's just a matter of somehow causing the two ends of the wire
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3 years ago

The center of gravity of a loaded truck depends on how the truck is packed. If it is 4.0 m high and 2.4 m wide, and its CG is 2.

Vitek1552 [10]

The slope of the road can be given as the ratio of the change in vertical

distance per unit change in horizontal distance.

The maximum steepness of the slope where the truck can be parked without tipping over is approximately <u>54.55 %</u>.

Reasons:

Width of the truck = 2.4 meters

Height of the truck = 4.0 meters

Height of the center of gravity = 2.2 meters

Required:

The allowable steepness of the slope the truck can be parked without tipping over.

Solution:

Let, <em>C</em> represent the Center of Gravity, CG

At the tipping point, the angle of elevation of the slope = θ

Where;

$tan\left(\theta \right) = \dfrac{\overline{AM}}{\overline{CM}}$

The steepness of the slope is therefore;

$\mathrm{The \ steepness \ of \ the \ slope}= \dfrac{\overline{AM}}{\overline{CM}} \times 100$

Where;

$\overline{AM}$ = Half the width of the truck = $\dfrac{2.4 \, m}{2}$ = 1.2 m

$\overline{CM}$ = The elevation of the center of gravity above the ground = 2.2 m

$\mathrm{The \ steepness \ of \ the \ slope}= \dfrac{1.2}{2.2} \times 100 \approx 54.55\%$

$tan\left(\theta \right) = \mathbf{\dfrac{2.2}{1.2}} = \dfrac{11}{6}$

$Elevation \ of \ the \ road \ \theta = arctan\left( \dfrac{6}{11} \right) \approx 28.6 ^{\circ}$

The maximum steepness of the slope where the truck can be parked is <u>54.55 %</u>.

Learn more here:

brainly.com/question/20793607

3 0

2 years ago

A child of mass 27 kg swings at the end of an elastic cord. At the bottom of the swing, the child's velocity is horizontal, and

snow_tiger [21]

Answer:

The magnitude of the rate of change of the child's momentum is 794.11 N.

Explanation:

Given that,

Mass of child = 27 kg

Speed of child in horizontal = 10 m/s

Length = 3.40 m

There is a rate of change of the perpendicular component of momentum.

Centripetal force acts always towards the center.

We need to calculate the magnitude of the rate of change of the child's momentum

Using formula of momentum

$\dfrac{dp}{dt}=F$

$\dfrac{dP}{dt}=\dfrac{mv^2}{r}$

Put the value into the formula

$\dfrac{dP}{dt}=\dfrac{27\times10^2}{3.40}$

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Hence, The magnitude of the rate of change of the child's momentum is 794.11 N.

7 0

3 years ago

I have a question regarding friction in rolling without slipping.

Solnce55 [7]

Explanation:

They probably put "rolls without slipping" in there to indicate that there is no loss in friction; or that the friction is constant throughout the movement of the disk. So it's more of a contingency part of the explanation of the problem.

(Remember how earlier on in Physics lessons, we see "ignore friction" written into problems; it just removes the "What about [ ]?" question for anyone who might ask.)

In this case, you can't ignore friction because the disk wouldn't roll without it.

As far as friction producing a torque... I would say that friction is a result of the torque in this case. And because the point of contact is, presumably, the ground, the friction is tangential to the disk. Meaning the friction is linear and has no angular component.

(You could probably argue that by Newton's 3rd Law there should be some opposing torque, but I think that's outside of the scope of this problem.)

Hopefully this helps clear up the misunderstanding for you.

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2 years ago