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777dan777 [17]
4 years ago
11

A cube has sides of 11.4 cm. What is its volume?

Chemistry
1 answer:
9966 [12]4 years ago
4 0
It is A) 1,482 cm3  ..............
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Why pure hydrogen is not used in ballons ?​
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Answer:  Hydrogen that is not used in balloons because hydrogen burns very easily.

pls mark brainliest

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3 years ago
Copper is an example of a(n)
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copper is not a stone, copper is not a consumption resource, and copper is not renewable, that means that :

d. nonrenewable resource

Explanation:

A nonrenewable source is a source of economic value that cannot be immediately displaced by natural means on a level equal to its destruction. Most fossil fuels, such as oil, natural gas, and coal are estimated nonrenewable resources in that their use is not sustainable because their production takes billions of years.

7 0
4 years ago
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a bar of gold is melted into liquid the liquid is then poured into a mold to make pieces of jewelry is the process a chemical ch
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6 0
3 years ago
My swimming pool is rectangular (16 feet by 34 feet) and has a depth of 6 feet. Lets imagine that my pool water is full to the t
Reil [10]

Answer:

Number of moles of photons required = 5.04 × 10⁴ moles

Explanation:

The energy of a photon can be calculated from Planck's equation E = hc/λ

Where h = 6.63 × 10-³⁴ Js and c, the velocity of light = 3.0 × 10⁸ m/s

Energy of one mole of photons = N₀ × hc/λ

wavelength of photon, λ = 520 nm = 5.20 × 10-⁷ m

Energy of one mole of photons = 6.02 × 10²³ × 6.63 × 10−³⁴ × 3 × 10⁸/5.20 × 10-⁷

Energy of one mole of photons = 2.30 × 10⁵ J/mol

Energy required to raise the temperature of a given mass of a substance, E = mcΔT

Where m is mass of substance,  c is specific heat capacity,  ΔT is temperature difference

Mass ofnwternin the pool = volume × density

Volume of water = Volume of swimming pool

Volume of water = 16 × 34 × 6 ft³ = 3264 ft³

1 ft³ = 28316.8 cm³; 3264 ft³ = 28316.8 × 3264 = 92426035.2 cm³

Density of water = 1 g/cm³

Mass of water = 92426035.2 cm³ × 1 g/cm³ = 92426035.2g

ΔT = 80°C - 50°C = 30°C, c = 4.18 J/g/K

Energy required to raise 92426035.2 g water by 30° C = 92426035.2 × 4.18 × 30

Energy required = 1.16 × 10¹⁰ J

Hence, number of moles of photons required = 1.16 × 10¹⁰ J/2.30 × 10⁵ J/mol

Number of moles of photons required = 5.04 × 10⁴ moles

5 0
3 years ago
A 2.75 kg sample of a substance occupies a volume of 250.0 cm3. Find its density in g/cm3.
satela [25.4K]
Density is 0.011 g/cm3.
5 0
3 years ago
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