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igor_vitrenko [27]
2 years ago
10

In leaves, the conducting tissues are found in the

Chemistry
1 answer:
Dafna1 [17]2 years ago
5 0

Answer:

b

Explanation:

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It is advised that the bromobenzene solution be added slowly to the magnesium-ether solution so that it isn't present in a high
lara [203]

Answer:

Biphenyl

Explanation:

The reaction of bromo benzene with magnesium-ether solution yields a Grignard reagent.

The byproduct of this reaction is biphenyl. It is formed when two unreacted bromobenzene molecules are coupled together.

Hence, It is advised that the bromobenzene solution be added slowly to the magnesium-ether solution so that it isn't present in a high concentration, thus reducing the amount of biphenyl by-product formed.

4 0
3 years ago
Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reactionP4(g) + 10 Cl2(g) → 4PCl5(s) ΔH°r
weqwewe [10]

Answer:

Therefore  \bigtriangledown H^\circ_{rxn}= -1835 KJ

Explanation:

Enthalpy is denoted by H.

Enthalpy: Total heat change in a chemical reaction is called enthalpy.

The change of entalpy of a reaction is denoted by \bigtriangledown H^\circ_{rxn}

Hass's Law:The change in enthalpy of any process can be determined by calculating the sum of change in enthalpy of each of the steps involved in the process.

g= gas

S= solid

P₄(g)+10Cl₂(g)→ 4Cl₅(s)       \bigtriangledown H^\circ_{rxn}=?

PCl₅(s)→ PCl₃(g)+Cl₂(g) .......(1)       \bigtriangledown H^\circ_{rxn}= +157KJ

P₄(g)+6Cl₂(g)→  4PCl₃(g).............(2)     \bigtriangledown H^\circ_{rxn}= -1207 KJ

If we flip a reaction the value of enthalpy will be change positive to negative or nagative to positive but the numerical value will be remain same.

We need rearrange the equation (1) because in the required equation Cl₂ is on the left side. So we flip the first equation.

PCl₃(g)+Cl₂(g)→PCl₅(s)......(3)          \bigtriangledown H^\circ_{rxn}= -157KJ

Multiplying 4 with equation (3)

4 PCl₃(g)+4Cl₂(g)→4PCl₅(s)......(4)          \bigtriangledown H^\circ_{rxn}=4×( -157)KJ= -628 KJ

Adding equation (2) and (4) we get

P₄(g)+6Cl₂(g)+4 PCl₃(g)+4Cl₂(g)→4PCl₃(g)+4PCl₅(s)    \bigtriangledown H^\circ_{rxn}=( -1207-628)KJ

⇒P₄(g)+10Cl₂(g)→4PCl₃(g)-4PCl₃(g)+4PCl₅(s)      \bigtriangledown H^\circ_{rxn}= - 1835KJ

⇒P₄(g)+10Cl₂(g)→ 4Cl₅(s)       \bigtriangledown H^\circ_{rxn}= -1835 KJ

Therefore  \bigtriangledown H^\circ_{rxn}= -1835 KJ

5 0
2 years ago
Identify and name the global<br> wind belts.<br> A<br> B<br> C<br> D<br> E<br> F<br> G
Finger [1]

Answer:

A. Polar Easterlies

B. Westerlies

C. Northeast Trades

D. Southeast Trades

E. Westerlies

F. Polar Easterlies

G. Hadley cell

Explanation:

I am pretty sure this is right. Hope that helps

8 0
2 years ago
A urine sample has a mass of 147 g and a density of 1.020 g/mL. What is the volume of this sample?
son4ous [18]

So we know that the equation for density is:

D=\frac{m}{V}

where D is the density, m is the mass in grams, and V is the volume in mL.

So since we know two of the variables, mass and density, we can solve for the volume:

\frac{1.020g}{mL}=\frac{147g}{V}

V=\frac{147g}{\frac{1.020g}{mL}}

V=144.12mL

Therefore, the volume of this urine sample is 144.12mL.

5 0
3 years ago
Synthesis<br> Decompisition<br> O Combustion<br> O Single Displacement<br> O Double Displacement
BabaBlast [244]

Answer:

Synthesis

Explanation:

Nothing else works

4 0
2 years ago
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