3 years ago

If f(x) = 1/9 x-2, what is f^-1 (x)?

Mathematics

1 answer:

babunello [35]3 years ago

5 0

Answer:

Step-by-step explanation:

let y = f(x) and rearrange making x the subject

Given

y = $\frac{1}{9}$ x - 2

Multiply through by 9

9y = x - 18 ( add 18 to both sides )

x = 9y + 18

Change y back into terms of x, hence

$f^{-1}$ (x) = 9x + 18

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