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4 years ago

What force causes Earth's centripetal motion?

Physics

2 answers:

Savatey [412]4 years ago

7 0

Answer:

gravity

Explanation:

Earth Motion in Centripetal direction is due to the centripetal force on the Earth.

As we know that Earth revolves around the sun with the force on Earth due to the Sun towards it.

If we assume the motion of Earth to be circular motion around the Sun then the force due to which Earth maintains its circular trajectory is known as Centripetal force.

Here this centripetal force is the gravitational force of Sun towards it

So correct answer would be

GRAVITY

Nastasia [14]4 years ago

5 0

Fam im just answering a question so i can get mine answered im sorry im no help but i think its gravity

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3 years ago

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No. A substance floats or sinks in another substance because of
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4 years ago

a person can throw a 300 gram ball at 25 m/s the maximum height the person can throw the ball on Earth?

jolli1 [7]

Answer:

Elevation =31.85[m]

Explanation:

We can solve this problem by using the principle of energy conservation. This consists of transforming kinetic energy into potential energy or vice versa. For this specific case is the transformation of kinetic energy to potential energy.

We need to first identify all the input data, and establish a condition or a point where the potential energy is zero.

The point where the ball is thrown shall be taken as a reference point of potential energy.

$E_{p} = E_{k} \\where:\\E_{p}= potential energy [J]\\ E_{k}= kinetic energy [J]$

m = mass of the ball = 300 [gr] = 0.3 [kg]

v = initial velocity = 25 [m/s]

$E_{k}=\frac{1}{2} * m* v^{2} \\E_{k}= \frac{1}{2} * 0.3* (25)^{2} \\E_{k}= 93.75 [J]$

$93.75=m*g*h\\where:\\g = gravity = 9.81 [m/s^2]\\h = elevation [m]\\replacing\\h=\frac{E_{k}}{m*g} \\h=\frac{93.75}{.3*9.81} \\h=31.85[m]$

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4 years ago

Describe the energy transfer when you touch a block of ice with your hand

nydimaria [60]

Answer:

Thermal energy always flows from the warmer object to the colder object. This causes your hand to get cold, while the ice absorbs your heat and melts.

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3 years ago

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A straight wire of length 0.62 m carries a conventional current of 0.7 amperes. What is the magnitude of the magnetic field made

anyanavicka [17]

Answer:

Magnetic field at point having a distance of 2 cm from wire is 6.99 x 10⁻⁶ T

Explanation:

Magnetic field due to finite straight wire at a point perpendicular to the wire is given by the relation :

$B=\frac{\mu_{0}I }{2\pi R }\times\frac{L}{\sqrt{L^{2}+R^{2} } }$ ......(1)

Here I is current in the wire, L is the length of the wire, R is the distance of the point from the wire and μ₀ is vacuum permeability constant.

In this problem,

Current, I = 0.7 A

Length of wire, L = 0.62 m

Distance of point from wire, R = 2 cm = 2 x 10⁻² m = 0.02 m

Vacuum permeability, μ₀ = 4π x 10⁻⁷ H/m

Substitute these values in equation (1).

$B=\frac{4\pi\times10^{-7}\times 0.7 }{2\pi \times0.02 }\times\frac{0.62}{\sqrt{(0.62)^{2}+(0.02) ^{2} } }$

B = 6.99 x 10⁻⁶ T

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3 years ago