Because telescopes in space<span> are able to provide accurate details of the </span>space<span> objects</span>
In uniform motion, the path is a straight line, and the object r moving along it at a constant speed.
Answer:
m v^2 / R = G M m / R^2 gravitational attraction = centripetal force
M = v^2 R / G solving for M
period = 6 h 25 min = (6 * 3600 + 25 * 60) sec = 23,100 sec = T
v = 2 pi R / T
M = 4 pi^2 R^3 / (G T^2)
M = 39.5 * (8.6E7)^3 / (6.67E-11 * 2.31E4^2)
M = 39.5 * 636 / (6.67 * 5.34) * 10^24
M = 7.05 * 10^26 kg
Answer:
3.71 eV
Explanation:
λ = Wavelength of light = 224 nm = 224 x 10⁻⁹ m
c = speed of electromagnetic wave = 3 x 10⁸ m/s
V₀ = stopping potential = 1.84 volts
W₀ = Work function of the metal = ?
Using the equation
= 5.94 x 10⁻¹⁹
= 3.71 eV
Answer:
Suppose the micrometeoroid weighed 1 g = .001 kg
Suppose also the spacecraft were moving at 18,000 mph (1.5 hrs per rev)
Usually, the smaller particle would be moving but for simplicity suppose that it were stationary wrt the ground
v = 18000 miles / hr * 1500 m/mile / 3600 sec/hr = 7500 m/s
KE = 1/2 * .001 kg * (7500 m)^2 = 28,125 Joules
One can see that 28000 Joules could be damaging amount of energy