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iogann1982 [59]
4 years ago
15

A ball A is thrown vertically upward from the top of a 30-m-high building with an initial velocity of 5 m/s. At the same instant

another ball B is thrown upward from the ground with an initial velocity of 20 m/s. Determine the height from the ground and the time at which they pass.

Physics
1 answer:
Serga [27]4 years ago
6 0

Explanation:

Below is an attachment containing the solution.

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A 64 kg swimmer jumps, with a velocity of 4.2 m/s, off the front of a 25 kg kayak when the kayak is moving forward at a velocity
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Answer:

3.88m/s

Explanation:

Using the law of conservation of momentum

m1u1+m2u2 = (m1+m2)v

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Required

Final velocity v

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v = 348.8/90

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Hence the velocity of the kayak after the swimmer jumps off is 3.88m/s

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