Answer:
Explanation:
Depression = .75 x 10⁻² m
Load = 120 g
Spring constant = 120g / .75 x 10⁻²
= 160 x 10² g / m
b )
Depression by player
= .48 x 10⁻² m
His weight
= .48 x 10⁻² x 160 x 10² g
= 76.8 kg
So he is eligible.
To solve the problem it is necessary to apply the concepts related to heat flow,
The heat flux can be defined as
Where,
k = Thermal conductivity
A = Area of cross-sectional area
d = Length of the rod
Temperature difference between the ends of the rod
Thermal conductivity of copper rod
Area of cross section of rod
Temperature difference
length of rod
Replacing then,
From the definition of heat flow we know that this is also equivalent
Where,
Mass per second
Latent heat of fusion of ice
Re-arrange to find 
Therefore the mass of ice per second that melts is 0.032g
Answer:
1250 N
Explanation:
length of wrench = 20 cm = 0.2 m
Write the length of wrench in vector form
r = 0.2 j metre
Direction of force= 
Let the magnitude of force is F
So, write the force in vector form
F = F
torque, T = 150 Nm
Torque = T = r x F
F = 1250 N
Thus, the magnitude of force is 1250 N.
Answer:
A.) r = 2t
B.) V = 33.5t^3
Explanation:
Given that a spherical balloon is being inflated and the radius of the balloon is increasing at a rate of 2 cm/s
A) Express the radius (r) of the balloon as a function of the time (t).
Since the rate = 2 cm/s that is,
Rate = radius/ time
Therefore,
2 = r/t
Make r the subject of formula
r = 2t
(B) If V is the volume of the balloon as a function of the radius, find V or and interpret it.
Let assume that the balloon is spherical. Volume of a sphere is;
V = 4/3πr^3
Substitute r = 2t into the formula
V = 4/3π(2t)^3
V = 4/3π × 8t^3
V = 32/3 × πt^3
V = 33.5t^3
The correct answer would be it would decrease.
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