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DaniilM [7]
3 years ago
9

The rate of filtration is Select one: a. modified by boundary layer effects. b. increased with increasing viscosity of the fluid

being filtered. c. decreased with increasing viscosity of the fluid being filtered. d. independent of the viscosity of the fluid being filtered.
Chemistry
1 answer:
brilliants [131]3 years ago
3 0

Answer:

c. decreased with increasing viscosity of the fluid being filtered.

Explanation:

Filtration is a method of separation which is useful in separating solids from the fluids (either liquids or gases) by adding a specific medium through which only fluid can pass. Fluid which passes through the filter is known as the filtrate.

Increasing the viscosity of the fluid which is being filtered decreases the rate of filtration as the liquid being more viscous take more time to cross the pores of the filter. Thus, rate of filtration is indirectly proportional to the viscosity of the fluid which is being filtered.

So, option C is correct.

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Determine the mole fractions and partial pressures of CO2, CH4, and He in a sample of gas that contains 1.20 moles of CO2, 1.79
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Answer :  The mole fraction and partial pressure of CH_4,CO_2 and He gases are, 0.267, 0.179, 0.554 and 1.54, 1.03 and 3.20 atm respectively.

Explanation : Given,

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Now we have to calculate the mole fraction of CH_4,CO_2 and He gases.

\text{Mole fraction of }CH_4=\frac{\text{Moles of }CH_4}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

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\text{Mole fraction of }CO_2=\frac{\text{Moles of }CO_2}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

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\text{Mole fraction of }He=\frac{\text{Moles of }He}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

\text{Mole fraction of }He=\frac{3.71}{1.79+1.20+3.71}=0.554

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Now we have to calculate the partial pressure of CH_4,CO_2 and He gases.

According to the Raoult's law,

p_i=X_i\times p_T

where,

p_i = partial pressure of gas

p_T = total pressure of gas  = 5.78 atm

X_i = mole fraction of gas

p_{CH_4}=X_{CH_4}\times p_T

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and,

p_{He}=X_{He}\times p_T

p_{He}=0.554\times 5.78atm=3.20atm

Thus, the partial pressure of CH_4,CO_2 and He gases are, 1.54, 1.03 and 3.20 atm respectively.

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