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DaniilM [7]
3 years ago
9

The rate of filtration is Select one: a. modified by boundary layer effects. b. increased with increasing viscosity of the fluid

being filtered. c. decreased with increasing viscosity of the fluid being filtered. d. independent of the viscosity of the fluid being filtered.
Chemistry
1 answer:
brilliants [131]3 years ago
3 0

Answer:

c. decreased with increasing viscosity of the fluid being filtered.

Explanation:

Filtration is a method of separation which is useful in separating solids from the fluids (either liquids or gases) by adding a specific medium through which only fluid can pass. Fluid which passes through the filter is known as the filtrate.

Increasing the viscosity of the fluid which is being filtered decreases the rate of filtration as the liquid being more viscous take more time to cross the pores of the filter. Thus, rate of filtration is indirectly proportional to the viscosity of the fluid which is being filtered.

So, option C is correct.

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OleMash [197]

Answer:

The enthalpy change during the reaction is -199. kJ/mol.

Explanation:

Mn(s)+2HCl(aq)\rightarrow  MnCl_2(aq)+H_2(g)

Mass of solution = m

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Density of solution = d = 1.00 g/mL

m=1.00 g/mL\times 100.0 mL = 100 g

First we have to calculate the heat gained by the solution in coffee-cup calorimeter.

q=m\times c\times (T_{final}-T_{initial})

where,

m = mass of solution = 100 g

q = heat gained = ?

c = specific heat = 4.18 J/^oC

T_{final} = final temperature = 23.1^oC

T_{initial} = initial temperature = 28.9^oC

Now put all the given values in the above formula, we get:

q=100 g \times 4.18 J/^oC\times (28.9-23.1)^oC

q=2,242.4 J=2.242 kJ

Now we have to calculate the enthalpy change during the reaction.

\Delta H=-\frac{q}{n}

where,

\Delta H = enthalpy change = ?

q = heat gained = 2.242 kJ

n = number of moles fructose = \frac{\text{Mass of manganese}}{\text{Molar mass of manganese}}=\frac{0.620 g}{54.94 g/mol}=0.0113 mol

\Delta H=-\frac{2.242 kJ}{0.0113 mol }=-199. kJ/mol

Therefore, the enthalpy change during the reaction is -199. kJ/mol.

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Answer:

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Input the data:

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And <u>solve for V</u>:

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