Question

In the interval 0 degrees Find the value for x in which sin=0.6691 To the nearest degree

Answer 1

Answer:

42° and 138°.

Step-by-step explanation:

Here we use the identity that

$sin (x) = sin(180-x )$.

Now, to find $x$, we make use of the inverse sine function:

$x = sin^{-1}(0.0091)$

$\boxed{ x = 42^o.}$

Another solution to this is

$x_0= 180 -x= 180-42 \\\\\boxed{ x_0 = 138^o}$

Thus, the values of $x$ in the interval $0$ for which $sin(x) =0.6691$ are 42° and 138°.