Answer:
A) False
B) False
C) True
D) False
Explanation:
A) False, because when leaving the field, the coil experiences a magnetic force to the right.
B) When the loop is entering the field, the magnetic flux through it will increase. Thus, induced magnetic field will try to decrease the magnetic flux i.e. the induced magnetic field will be opposite to the applied magnetic field. The applied magnetic field is into the plane of figure and thus the induced magnetic field is out of the plane of figure. Due to that reason, the current would be counterclockwise. So the statement is false.
C) When the loop is leaving the field, the magnetic flux through the loop will decrease. Thus, induced magnetic field will try to increase the magnetic flux i.e. the inducued magnetic field will be in the same direction as the applied magnetic field. The applied magnetic field is into the plane of figure and thus the induced magnetic field is also into the plane of figure. Due to that reason, the current would be clockwise. So the statement is true.
D) False because when entering the field magnetic force will be toward left side
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Answer:
Fx = 32.14 [N]
Fy = 38.3 [N]
Explanation:
To solve this problem we must decompose the force vector, for this we will use the angle of 50 degrees measured from the horizontal component.
F = 50 [N]
Fx = 50*cos(50) = 32.14 [N]
Fy = 50*sin(50) = 38.3 [N]
We can verify this result using the Pythagorean theorem.
![F = \sqrt{(32.14)^{2}+ (38.3)^{2}} \\F = 50 [N]](https://tex.z-dn.net/?f=F%20%3D%20%5Csqrt%7B%2832.14%29%5E%7B2%7D%2B%20%2838.3%29%5E%7B2%7D%7D%20%5C%5CF%20%3D%2050%20%5BN%5D)
Answer:
the engine cool to 40
at 14.07 minutes
Explanation:
Given information
T(5) = 70
= 100
C = 15
Newton's law of cooling :
T(t) = C + ( - C) 
where
T(t) = temperature at any given time
C = surrounding temperature
= initial temperature of heated object
k = cooling constant
to find the the time when the engine will be cooled down to 40, we first need to find the cooling constant, k
when t = 5, T(5) = 70
so,
T(t) = C + ( - C)
T(5) = 15 + (100 - 15) 
70 = 15 + (85)
= (70 - 15) / 85
-5k = ln (55/85)
k = - ln (55/85) / 5
k = 0.087
thus, we have the eqaution
T(t) = 15 + (85) 
now we can determine the time when T(t) = 40
40 = 15 + (85)
= (40-15)/85
-0.0087t = ln (25/85)
t = - ln (25/85)/0.087
t = 14.07 minutes
