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3 years ago

8

Balloon like cell organelle in the cytoplasm that can store food, water, and wastes, also provides pressure against the cell wal

l for cellular support in plant cells
A
Vacuoles
B
Mitochondrion
C
Ribosomes
D
Nucleus
PLSSSSSS HELP MEEEEE!! :C

1 answer:

melisa1 [442]3 years ago

8 0

Answer:

Vacuoles......final answer

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Why does the presence of redshift in spectra of galaxies support an understanding of an expanding universe?

xenn [34]

Explanation:

Doppler's Effect: If a source is moving towards the observer the frequency of the waves emitted by the source will increase( wavelength will decrease). If the source is moving away from the observer the frequency of the waves emitted by the source will decrease( wavelength will increase). The best example of this is the changing frequency of siren of an ambulance as it moves towards us and then away from us.

The same phenomenon can be observed in celestial objects. When the object will move towards us the wavelength will decrease thus the spectrum will be shifted towards the blue part. This is known as blue shift.

If the object moves away from us the wavelength will increase and thus the spectrum will be shifted towards red part. This is know as Red-shift. This is because red has longer wavelength (620 - 750nm) than blue (450-495nm)

Thus if a galaxy shows us red-shifted spectra it means that it is moving away from us. we have observed this phenomenon in various galaxies thus supporting the expanding universe theory.

7 0

3 years ago

Una barra de hierro cuya longitud inicial es de 2m se le incrementa su temperatura de 20 °C a 120 °C ¿Cuál es la longitud final

Ksivusya [100]

Answer:

1.9976 m

Explanation:

An iron bar whose initial length is 2m has its temperature increased from 20 ° C to 120 ° C. What is the final length of the bar? (consider that the coefficient of expansion of iron) is 1.2 x 10-5 1 / ° C (3 points)

Given that,

Initial length of an iron bar, $L_0=2\ m$

The temperature increased from 20°C to 120°C

The coefficient of expansion of iron is $1.2\times 10^{-5}\ /^{\circ} C$

We need to find the final length of the bar.

The linear expansion equation is given by :

$\Delta L=\alpha L\Delta T$

Where $\Delta L$ is the change in length

$\Delta L=1.2\times 10^{-5}\times 2\times (120-20)\\\\=0.0024\ m$

Also, $\Delta L = L_o-L$

L is final length

$0.0024= 2-L\\\\L=2-0.0024\\\\=1.9976\ m$

So, the final length of the bar is 1.9976 m

8 0

2 years ago

The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasin

Ganezh [65]

Answer:

The current in the circuit decrease slowly .

Explanation:

Given as :

For the electrical circuit

The voltage V in the circuit is slowly decreasing

The resistance R of the resistor slowly increasing after heating

Now, From Ohm's Law

Voltage is directly proportional to the flow of current through circuit

I.e V ∝ I

Or. V = R × I

where R is the proportionate constant and this is the resistance of the resistor

whose property is to opposes the flow of current in the circuit

So, If R value more then current I reduces in the circuit

∵ Here in the circuit , The resistance is slowly increasing, so, current I is slowly decreasing .

Hence The current in the circuit decrease slowly . answer

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3 years ago

A car is initially moving at 20 m/s east and a little while later it is moving at 10 m/s north. Which of the following best desc

Nina [5.8K]

Answer:d

Explanation:

Given

First car is moving towards east with velocity 20 m/s

$\vec{v_1}=20\hat{i}$

then it turns towards north then velocity is

$\vec{v_2}=10\hat{j}$

suppose car takes t sec to change its path so average acceleration is given by

$a=\frac{v_2-v_1}{t}$

$a=\frac{1}{t}(10\hat{j}-20\hat{i})$

So average acceleration is towards North of west.

5 0

3 years ago

A sock stuck to the inside of the clothes dryer spins around the drum once every 2.0 s at a distance of 0.50 m from the center o

Rashid [163]

a) 1.57 m/s

The sock spins once every 2.0 seconds, so its period is

T = 2.0 s

Therefore, the angular velocity of the sock is

$\omega=\frac{2\pi}{T}=\frac{2\pi}{2.0}=3.14 rad/s$

The linear speed of the sock is given by

$v=\omega r$

where

$\omega$ is the angular velocity

r = 0.50 m is the radius of the circular path of the sock

Substituting, we find:

$v=(3.14)(0.50)=1.57 m/s$

B) Faster

In this case, the drum is twice as wide, so the new radius of the circular path of the sock is twice the previous one:

$r' = 2r = 1.00 m$

At the same time, the drum spins at the same frequency as before, therefore the angular frequency as not changed:

$\omega' = \omega = 3.14 rad/s$

Therefore, the new linear speed would be:

$v'=\omega' r' = \omega (2r)$

And substituting,

$v'=(3.14)(1.00)=3.14 rad/s = 2v$

So, we see that the linear speed has doubled.

8 0

2 years ago