<span>Assuming the speeds of both the stick and Ingrid are taken from a stationary point, the velocities of both Ingrid and the stick will be subtracted to see how much faster the stick is going.
16 - 9
= 7 km/h is the speed of the stick relative to Ingrid</span>
Answer:
Therefore the speed of q₂ is 1961.19 m/s when it is 0.200 m from from q₁.
Explanation:
Energy conservation law: In isolated system the amount of total energy remains constant.
The types of energy are
- Kinetic energy.
- Potential energy.
Kinetic energy 
Potential energy =
Here, q₁= +5.00×10⁻⁴C
q₂=-3.00×10⁻⁴C
d= distance = 4.00 m
V = velocity = 800 m/s
Total energy(E) =Kinetic energy+Potential energy
+ 

=(1280-337.5)J
=942.5 J
Total energy of a system remains constant.
Therefore,
E
+ 




m/s
Therefore the speed of q₂ is 1961.19 m/s when it is 0.200 m from from q₁.
The diagram is missing; however, we know that the intensity of a sound wave is inversely proportional to the square of the distance from the source:

where I is the intensity and r is the distance from the source.
We can assume for instance that the initial distance from the source is r=1 m, so that we put

The intensity at r=3 m will be

Therefore, the sound intensity has decreased by a factor

.