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3 years ago

A boxer can hit a heavy bag with great force. Why can't he hit a piece of tissue paper in midair with the same amount of force?

Physics

1 answer:

12345 [234]3 years ago

6 0

Answer:

This is due to impulse

Explanation:

Impulse equal to mΔv and FΔt

You can set these equal as mΔv = FΔt

When a boxer punches a tissue, it is like punching a cushion or a pillow. The time that the hit takes is much grater than if they were to hit something solid. In addition, the change in velocity of the boxer's arm would be much greater when they hit a punching bag. In this equation, the greater the time, the less force that is needed.

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A uniform solid sphere has mass m= 7 kg and radius r= 0. 4 m. What is its moment of inertia about an axis tangent to its surface

lilavasa [31]

The moment of inertia of a uniform solid sphere is equal to 0.448 $kgm^2$ .

<u>Given the following data:</u>

Mass of sphere = 7 kg.

Radius of sphere = 0.4 meter.

<h3>How to calculate moment of inertia.</h3>

Mathematically, the moment of inertia of a solid sphere is given by this formula:

$I=\frac{2}{5} mr^2$

<u>Where:</u>

I is the moment of inertia.

m is the mass.

r is the radius.

Substituting the given parameters into the formula, we have;

$I=\frac{2}{5} \times 7 \times 0.4^2\\\\I=2.8 \times 0.16$

I = 0.448 $kgm^2$ .

Read more on inertia here: brainly.com/question/3406242

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2 years ago

A grandfather clock is "losing" time because its pendulum moves too slowly. Assume that the pendulum is a massive bob at the end

IgorC [24]

Answer:

d) shortening the string

Explanation:

Time period of a pendulum clock is dependent on two factors namely:length and acceleration due to gravity.

When a clock loses time, the time period of the pendulum clock increases.

This however can be corrected by decreasing the length of the pendulum.The time period of the pendulum clock is not dependent on the mass of the bob. The time period of the pendulum clock can be corrected only by changing the length of the pendulum string.

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3 years ago

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While strolling downtown on a Saturday afternoon, you stumble across an old car show. As you are walking along an alley toward a

snow_tiger [21]

Answer:

1.44 m/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

$v=u+at\\\Rightarrow v=0+a\times 5\\\Rightarrow v=5a$

This velocity will be the initial velocity of the car when it passes through the first building

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The acceleration of the car is 1.44 m/s²

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RUDIKE [14]

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gizmo_the_mogwai [7]

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