Average  force on the window: 0.32 N
Explanation:
The average force exerted on the window is given by Newton's second law

where
 is the net change in momentum of the hailstones in a time interval of
 is the net change in momentum of the hailstones in a time interval of 
In order to find the change in momentum, we have to consider only the component of the hailstone's momentum perpendicular to the window, therefore:
 is the initial momentum of one hailstone, with
 is the initial momentum of one hailstone, with
m = 7 g = 0.007 kg is the mass
 is the initial speed
 is the initial speed
 is the angle with the window
 is the angle with the window
The final momentum is

where
v = 4.5 m/s is the final speed (the  collision is elastic so the speed is equal, while the direction changes)
 (after the rebound, the direction has changed)
 (after the rebound, the direction has changed)
So the change in momentum of 1 hailstone is

We are interested only in the magnitude, so

There are 595 hailstones hitting the window in 49 s, so the total change in momentum is

And therefore, the average force on the window is

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