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Murrr4er [49]
3 years ago
14

A rock is dropped from a height of 2.7m. How fast is it going when it hits the ground?

Physics
1 answer:
Lana71 [14]3 years ago
4 0
Use the formula Vf^2 = Vi^2 + 2a(d)


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What vertical distance Δy does a free-falling particle travel from the moment it starts to the moment it reaches a speed of 7.9
mr_godi [17]

Answer:

3.2 m

Explanation:

The equation to use to solve this problem is:

v_f^2 = v_i^2 + 2 a \Delta y

where

v_f is the final velocity

v_i is the initial velocity

a is the acceleration

\Delta y is the distance covered

For the particle in free-fall in this problem, we have

v_i = 0 (it starts from rest)

v_f = 7.9 m/s

g=9.8 m/s^2 (acceleration due to gravity)

By re-arranging the equation, we can find the distance travelled:

\Delta y = \frac{v_f^2 -v_i^2}{2a}=\frac{(7.9 m/s)^2-0^2}{2(9.8 m/s^2)}=3.2 m

5 0
3 years ago
The force exerted by electrically changed objects
MAVERICK [17]

Answer:

Electrostatic Force...or a non-contact force

Explanation:

8 0
3 years ago
Three-fourths of the elements on the
77julia77 [94]

Answer:

b

Explanation:

because the metalloids are the thing in the middle

8 0
3 years ago
In a research facility, a person lies on a horizontal platform which floats on a film of air. When the person's heart beats, it
anastassius [24]

Answer: 3.48g

Explanation:

here, we will be using conservation of momentum to solve the problem. i.e the total momentum remains unchanged, unless an external force acts on the system. We'll in thus question, there is no external force acting in the system.

Remember, momentum = mass * velocity, then

mass of blood * velocity of blood = combined mass of subject and pallet * velocity of subject and pallet

Velocity of blood = 56.5cm = 0.565m

mass of blood * 0.565 = 54kg * (0.000063/0.160)

mass of blood * 0.565 = 54 * 0.00039375

mass of blood * 0.565 = 0.001969

mass of blood = 0.00348kg

Thus, the mass of blood that leaves the heart is 3.48g

7 0
3 years ago
Read 2 more answers
Rita jeptoo of kenya was the first female finisher in the 110th boston marathon. she ran the first 10.0 km in a time of 0.5689 h
stira [4]

Part a

Answer: 17.58 km/h

Average speed=\frac{Total\hspace{1mm}Distance}{Total\hspace{1mm}Time}

Total Distance =10 km

Total time =0.5689 h

\Rightarrow Average speed=\frac{10\hspace{1mm}km}{0.5689\hspace{1mm}h}=17.6 \hspace{1mm}km/h

Part b

Answer: 17.626 km/h

Average speed=\frac{Total\hspace{1mm}Distance}{Total\hspace{1mm}Time}

Total Distance =42.195 km

Total time =2.3939 h

\Rightarrow Average speed=\frac{42.195\hspace{1mm}km}{2.3939\hspace{1mm}h}=17.626\hspace{1mm}km/h

8 0
3 years ago
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