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bazaltina [42]
3 years ago
11

John is preparing for his way to school. His house is 30 km away. What time will he be in school if he leaves his house at 6:30

AM and travels at an average speed of 40 km/hr?
Physics
1 answer:
Goshia [24]3 years ago
7 0

Answer:

Jio will be at school at 7:15 a.m.

Explanation:

Formula:

t= s/v =(30km)/(40km/h) =0.75•60min=45min.

Then, Jio will be at school at 6:30a.m. + 45min =7:15a.m.

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A proton is held at rest in a uniform electric field. When it is released, the proton will lose its kinetic energy.

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Option (A) and (F)

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Read 2 more answers
An object is thrown directly downward from the top of a very tall building. The speed of the object just as it is released is 17
Softa [21]

Answer:

distance cover is  = 102.53 m

Explanation:

Given data:

speed of object is 17.1 m/s

t_1 = 3.32 sec

t_2 = 5.08 sec

from equation of motion we know that

d_1 = vt_1 + \frac{1}{2} gt_1^2

where d_1 is distance covered in time t1

sod_1 = 17.1 \times 3.32 + \frac{1}{2} 9.8 \times 3.32^2=

d_1 = 110.78 m

d_2 = vt_2 + \frac{1}{2} gt_2^2

where d_2 is distance covered in time t2

d_2 = 17.1 \times 5.08 + \frac{1}{2}\times9.8 \times 5.08^2

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distance cover is  = 213.31 - 110.78 = 102.53 m

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3 years ago
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