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3 years ago

Underground water that seeps out onto the land's surface is called a

Physics

2 answers:

Artemon [7]3 years ago

7 0

The answer is A............................................................

gavmur [86]3 years ago

6 0

The answer is a. spring

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A horizontal metal bar oriented east-west drops straight down in a location where the earth's magnetic field is due north. as a

amid [387]

Metal bar is aligned along East- West direction and it is dropped vertically down

So its velocity is along -Z direction,

Now the Earth's magnetic field is towards north so its towards +Y direction

now we have formula for force on a moving charge

$F = q(v X B)$

v = - z direction

B = + y direction

now by the above formula

$F = q(v(-k) X B(j))$

$F = qvB (i)$

So force is towards East

so all positive charge is towards East end

5 0

3 years ago

When driving at night switch to low-beams whenever you come within ___ ft of an oncoming vehicle.

Ainat [17]

B. 500ft. If you are driving at night with high beams on you must dim them within 500 feet of an oncoming vehicle.

3 0

3 years ago

Read 2 more answers

It is impossible to destroy __________.

fredd [130]

C.energy
The law of conservation of energy says that energy can neither be created nor destroyed.

6 0

3 years ago

Read 2 more answers

How can you degauss a magnet temporarily?

EleoNora [17]

Answer:

Demagnetization processes include heating past the Curie point, applying a strong magnetic field, applying alternating current, or hammering the metal.

Explanation:

7 0

3 years ago

Two forces, F⃗ 1F→1F_1_vec and F⃗ 2F→2F_2_vec, act at a point. F⃗ 1F→1F_1_vec has a magnitude of 9.20 NN and is directed at an a

BARSIC [14]

Answer:

The x component of the resultant force is -7.27N.

Explanation:

To obtain the x component of the resultant force, first we have to know the x components of the other forces. To do this, we just have to do some trigonometry:

$|F_{1x}|=|F_1|\cos\theta_1=9.20N\cos62.0\°=4.31N \\|F_{2x}|=|F_2|\cos\theta_2=5.00N\cos53.6\°=2.96N$

Since both vectors are in the left side of the y-axis, they have a negative x component. So:

$F_{1x}=-4.31N;\\F_{2x}=-2.96N$

Finally, we sum both components to obtain the component of the resultant force:

$F_{Rx}=-4.31N-2.96N=-7.27N$

In words, the x component of the resultant force is -7.27N.

6 0

3 years ago