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Alenkasestr [34]
3 years ago
10

Underground water that seeps out onto the land's surface is called a

Physics
2 answers:
Artemon [7]3 years ago
7 0
The answer is A............................................................
gavmur [86]3 years ago
6 0
The answer is a. spring

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nikdorinn [45]
The correct answers are as follows:
<span>1) hydrogenous sediment

2)sand and gravel

3) They rapidly break down at surface temperatures and pressures.</span>
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3 years ago
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A rock is thrown horizontally from a bridge with a speed of 29.0 m/s. if the rock is 23.7 meters above the river at the moment o
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It would be 1.5 meters im sure form that distance to me is that nswe

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3 years ago
Consider the sections of two circuits illustrated above. Select True or False for all statements. After connecting c and d to a
Basile [38]

Answer:

Follows are the solution to the given question:

Explanation:

In this question the missing file of the circuit is not be which is defined in attached file please find it.

In Option 1, this statement is true because the current is on R_3 \  and \ R_4, that is the same.

In option 2, this statement is false because Rcd=R_3+R_4 therefore it implies that Rcd is always larger then R_3.

In option 3,  this statement is true because the voltage of R_1 \ and \ R_2 is always equal.

In option 4, this statement is true because Rab= \frac{1}{(\frac{1}{R1}+\frac{1}{R2})}=\frac{R1R2}{(R1+R2)}. \frac{R2}{(R1+R2)}is always smaller then 1 therefore,R_1 \times (\frac{R2}{(R1+R2)}) is always equal to R1.

5 0
3 years ago
6. Aaron will run from home at y mph and walk back at x mph. how much distance does he need to travel to spend a total of t hour
Kisachek [45]

Answer:

Total distance, d=\dfrac{xyt}{(x+y)}

Explanation:

It is given that,

Speed of Aaron from home is y mph and walk back at x mph. Let t is the total time he spend in walking and jogging. Let d is the distance covered.

We he moves from home to destination, time is equal to, \dfrac{d}{x}

Similarly, when he move back to home, time taken is equal to \dfrac{d}{y}

Total time taken is equal to :

\dfrac{d}{x}+\dfrac{d}{y}=t

d(\dfrac{1}{x}+\dfrac{1}{y})=t

d=\dfrac{t}{(\dfrac{1}{x}+\dfrac{1}{y})}

d=\dfrac{xyt}{(x+y)}

So, the distance he speed in walking and jogging is \dfrac{xyt}{(x+y)}. Hence, this is the required solution.

8 0
3 years ago
Wrench is to Hammer as ​
Elanso [62]

Answer:

Pencil is to pen

Step by step explanation:

They are similar items, as they are both tools, but are different as to how they function.

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