Answer:
Explanation:
First of all we shall find out net electric field at q₃ due to both of the remaining charges .
electric field due to charge Q = k Q / r² where k = 9 x 10⁹ Q is amount of charge and r is distance of point
electric field due to charge 105 x 10⁻⁶ C
= 9 x 10⁹ x 105 x 10⁻⁶ / .95²
= 1.047 x 10⁶ N/C .
It will act away from q₂
electric field due to charge 53 x 10⁻⁶ C
= 9 x 10⁹ x 53 x 10⁻⁶ /( .5+.95)²
= 0.227 x 10⁶ N/C .
It will act towards q₁
These fields are in opposite direction so
net field E = 0.82 x 10⁶ N/C.
It will act away from q₂ .
Force on q₃ due to net field
= q₃ E
= 88 x 10⁻⁶ x 0.82 x 10⁶
= 72.16 N
The direction of this field will be towards q₂ because force on negative charge in a field is always in a direction opposite to the direction of the field.
Answer:
A. kgm/second/second or Newton
Explanation:
Force is measured in Newton's or (N)
Answer:
Explanation:
66 km/hr = 18.3 m/s
½mv² = ½kx²
k = mv²/x² = 1200(18.3²)/2.2² = 83,333 = 83 kN/m
Answer:
-3.9 m/s
Explanation:
Given that
Initial velocity, u of both bodies = 0
Initial momentum of the bodies = 0
Final velocity, v of the 3M block = 1.3 m/s
Mass M of the block A = M
Mass m of the block B = 3M
To solve this question, we would have to use the law of conservation of momentum. The law states that in any system, momentum is always conserved. Thus, initial momentum = final momentum. Mathematically, we have
M * V(a) + 3M * V(b) = 0
The velocity of the block 3M block is V(b) has been given to be 1.3 m/s, so then
M.V(a) = - 3M * 1.3
V(a) = -3.9M/M
V(a) = -3.9 m/s
Answer:
9.36*10^11 m
Explanation
Orbital velocity v=√{(G*M)/R},
G = gravitational constant =6.67*10^-11 m³ kg⁻¹ s⁻²,
M = mass of the star
R =distance from the planet to the star.
v=ωR, with ω as the angular velocity and R the radius
ωR=√{(G*M)/R},
ω=2π/T,
T = orbital period of the planet
To get R we write the formula by making R the subject of the equation
(2π/T)*R=√{(G*M)/R}
{(2π/T)*R}²=[√{(G*M)/R}]²,
(4π²/T²)*R²=(G*M)/R,
(4π²/T²)*R³=G*M,
R³=(G*M*T²)/4π²,
R=∛{(G*M*T²)/4π²},
Substitute values
R=9.36*10^11 m
