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3 years ago

In fiction, a symbol can be described as __________.

Physics

1 answer:

abruzzese [7]3 years ago

5 0

In fiction, a symbol can be described as an object that stands for something other than itself.

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The objective lens of a microscope has a focal length of 5.5mm. Part A What eyepiece focal length will give the microscope an ov

son4ous [18]

Complete Question

The distance between the objective and eyepiece lenses in a microscope is 19 cm . The objective lens has a focal length of 5.5 mm .

What eyepiece focal length will give the microscope an overall angular magnification of 300?

Answer:

The eyepiece focal length is $f_e = 0.027 \ m$

Explanation:

From the question we are told that

The focal length is $f_o = 5.5 \ mm = -0.0055 \ m$

This negative sign shows the the microscope is diverging light

The angular magnification is $m = 300$

The distance between the objective and the eyepieces lenses is $Z = 19 \ cm = 0.19 \ m$

Generally the magnification is mathematically represented as

$m = [\frac{Z - f_e }{f_e}] [\frac{0.25}{f_0} ]$

Where $f_e$ is the eyepiece focal length of the microscope

Now making $f_e$ the subject of the formula

$f_e = \frac{Z}{1 - [\frac{M * f_o }{0.25}] }$

substituting values

$f_e = \frac{ 0.19 }{1 - [\frac{300 * -0.0055 }{0.25}] }$

$f_e = 0.027 \ m$

5 0

3 years ago

Convert 10 kilowatt to watt

Nataly [62]

Answer:

0.01 kilowatts cubed

Explanation:

just ask alexa lol

3 0

3 years ago

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John enjoys watching crime shows and his best subject in school was chemistry. What might be a good career for him to explore? I

Vera_Pavlovna [14]

The answer is D forensic investigator

4 0

3 years ago

Read 2 more answers

Consider a bicycle that has wheels with a circumference of 2 m. Solve for the linear speed of the bicycle when it's wheels rotat

Yuliya22 [10]

Answer:0.3183m/s

Explanation: V=wr

V=linear velocity

W= angular velocity

P=2πr

r=p/2π

r=2/2π

r= 1/3.142

r=0.3183

V= 0.3183*1

V=0.3183m/s

4 0

3 years ago

You have a 2.2 m long copper wire. you want to make an n-turn current loop that generates a 1.9 mt magnetic field at the center

ArbitrLikvidat [17]

The trick here is that there are two variables, Diameter of the coil and number of turns in it. So, in order to solve it, we will need two equations in D and N
Since we are making coil, formula for magnetic field will be B = μₒni/D
D = μₒni/B = 4π x 10^(-7) x (N) x (2.2) / (1.6)x10^(-3) = 1.7 x 10^(-3) x N = D
Another equation will be from the wire's length.
Total length = Circumference of one loop x No. of turns = πD x N = 2.2
We will eliminate N because we need D.
N = 2.2 / πD
Substitute in 1st equation.
1.7 x 10^(-3) x 2.2 / π = D^2
<span> D = 0.034 m = 3.4 cm </span>

7 0

3 years ago