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3 years ago

Describe how you would prepare a supersaturated solution.

Chemistry

2 answers:

earnstyle [38]3 years ago

5 0

Answer:

To prepare a supersaturated solution, the added amount must be higher than the solubility for the given volume of solvent

Explanation:

Hello,

This could be answered by knowing that all the solutes have a property called solubility which accounts for the maximum amount of it that can be thoroughly dissolved into a specific solvent. Thus, to prepare a supersaturated solution, the added amount must be higher than the solubility for the given volume of solvent at a specific temperature. For example, at 20°C, 45.8g of aluminium chloride are completely dissolved into 100 mL of water, so at that amount, the solution will be saturated, thus, if one adds more than 45.8g the solution will start being supersaturated.

Best regards.

Anastasy [175]3 years ago

4 0

To make a supersaturated solution, make a saturated solution of sugar by adding 360 grams of sugar to 100 mL of water at 80 degrees Celsius. When the water cools back down to 25 degrees, that 360 grams of sugar will still be dissolved even though the water should only dissolve 210 grams of sugar.

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For an alloy that consists of 33.5 wt% Pb and 66.5 wt% Sn, what is the composition (a) of Pb (in at%), and (b) of Sn (in at%)? T

Tju [1.3M]

Answer:

Pb: 22.4 at%

Sn: 77.6 at%

Explanation:

It is possible to find at% of Pb and Sn converting mass in moles using molar mass assuming a basis of 100g, thus:

Pb: 33.5g × (1mol / 207.2g) = 0.1617mol

Sn: 66.5g × (1mol / 118.7g) = 0.5602mol

Total moles: 0.1617mol + 0.5602mol = 0.7219mol

Composition in at%:

Pb: 0.1617mol / 0.7219mol × 100 = 22.4 at%

Sn: 0.5602mol / 0.7219mol × 100 = 77.6 at%

I hope it helps!

5 0

3 years ago

Do you know what this is ??

Sonja [21]

Answer:

is there a pic or anything?

8 0

3 years ago

Read 2 more answers

a 0.5678 of KHP required 26.64cm³ of NaOH to complete neutralization.calculate the molarity of the NaOH solution

vladimir2022 [97]

Answer:

Explanation:

0.5678 G X GRAMS

KHC8H4O4 + NaOH = NaKC8H4O4 + H2O

1 MOL 1 MOL

0.5678G X 204G/MOL = 0.00278 MOL KHC8H4O4

0.00278 MOL KHC8H4O4 X 1 MOLE NaOH/1 MOLE KHC8H4O4=0.00278 MOL NaOH

0.00278 MOL NaOH/26.26ml=0.106 molar

4 0

3 years ago

QUESTION 4

jeka94

Moles of iron = 7.30

<h3>Further explanation</h3>

Given

mass of iron = 408.67 g

Required

moles of atoms

Solution

The mole is the number of particles contained in a substance

1 mol = 6.02.10²³

Moles can also be determined from the amount of substance mass and its molar mass

mol iron-Fe (Ar = 56 g/mol)

mol = mass : MW

mol = 408.67 g : 56

mol = 7.30

8 0

3 years ago

An initial ph of 4.0 and an equivalence point at ph = 9.1 corresponds to a titration curve for a

notka56 [123]

Hello!

An initial pH of 4,0 and an equivalence point at pH=9,1 corresponds to a titration curve for a weak acid to which strong base is added

An example would be the titration of Acetic Acid (CH₃COOH) with Sodium Hydroxide (NaOH)

CH₃COOH + NaOH → CH₃COONa + H₂O

The initial pH will be acid because only the Acetic Acid is present. In the equivalence point, there are no CH₃COOH nor NaOH present, and the only species responsible for pH is CH₃COONa. This is a weak base, as evidenced by the following reaction:

CH₃COO⁻ + H₂O ⇄ CH₃COOH + OH⁻

So, in the equivalence point, the pH will be basic. These observations help us conclude that this titration is of a weak acid with a strong base.

Have a nice day!

7 0

3 years ago