Answer:
15 or 65 or 7
Explanation:
I am not sure which one, but i think it is one of these
20.21*10^-4 mg/L is the concentration.
Explanation:
Given:
Pressure=1 atm.
Temperature= 0 degrees
Volume percent of air is 21%
Henry's Law constant K = 2.28 x 10^-3 mole/L-atm
The partial pressure of oxygen is 0.21 atm.
By Henry's law:
Concentration= K X Partial pressure
= 2.28*10^-3 *0.21
= 4.79*10^-4 moles/litre
Since, at STP 1 mole of oxygen occupies volume of 22.4L
concentration =mass/volume
mass = 4.79*10^-4-4*22.4
= 20.21*10^-4 mg
20.21*10^-4 mg/L is the concentration.
The answer is (2) 2. First of all, a greater hydronium ion concentration means more acidic, so we need a lower pH. Also, you need to remember that pH is on a base 10 log scale. This means that a difference by a factor of 10 in concentration is a difference of 1 on the pH scale. So since the difference is a factor of 100 (10^2), the difference is 2. We already established that the pH must be lower, so your answer is 4 - 2 = 2.
Answer:
because of the moons gravity
Explanation:
Answer:
The compounds are arranged from the least heat of combustion to the highest (in order of increasing heat of combustion).
Propane--> butane --> pentane.
Explanation:
Hydrocarbons are compounds which contains carbon and hydrogen only. Alkane is called a saturated hydrocarbon because all four bonds of carbon are single bonds. Examples of alkanes include: pentane, propane and butane. One of the chemical properties of alkanes includes combustion reaction.
In COMBUSTION REACTION, alkanes burns in air (oxygen) to produce carbon dioxide and water.The heat released on complete combustion of one mole of a substance is called HEAT OF COMBUSTION.
The heat of combustion of saturated hydrocarbon ( alkanes) increases with increase in number of carbon atoms in a molecule. This is due to more carbon available for burning and more number of bonds undergoing changes. Therefore in the arrangement of the given compounds, PENTANE has the highest heat of combustion while PROPANE is the least.
